本文整理汇总了C#中AIState.Equals方法的典型用法代码示例。如果您正苦于以下问题：C# AIState.Equals方法的具体用法？C# AIState.Equals怎么用？C# AIState.Equals使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类AIState的用法示例。
在下文中一共展示了AIState.Equals方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: RemoveState
/**
* Removes a state from the machine and updates transition matrix.
* TODO: Checks to make sure we're removing an existing state.
* TODO: If we are removing CURRENT state, then throw warning and transition.
**/
public void RemoveState(AIState state)
{
int removeIndex = StateNames.IndexOf(state);
int newVectorIndex = 0;
int newProbIndex = 0;
double[][] newTransitionMatrix = new double[NumStates - 1][];
/**
* If removing currentState, or only one state left.
**/
if ((NumStates == 1) || !(StateNames.Contains(state)))
{
return;
}
/**
* For every row vector in the transitional matrix:
**/
for (int vectorIndex = 0; vectorIndex < NumStates; vectorIndex++)
{
// If it doesn't correspond to the state we are removing:
if (vectorIndex != removeIndex)
{
newProbIndex = 0;
newTransitionMatrix[newVectorIndex] = new Double[NumStates - 1];
/**
* Then for every probability in this vector:
**/
for (int probIndex = 0; probIndex < NumStates; probIndex++)
{
// If it doesn't correspond to the state we are removing:
if (probIndex != removeIndex)
{
/**
* Then copy it into the new Transitional Matrix
* adjusting value for the removed state so as to
* still uphold the transition matrix property of
* every vector adding up to 1.0
**/
newTransitionMatrix[newVectorIndex][newProbIndex] =
TransitionMatrix[vectorIndex][probIndex] +
TransitionMatrix[vectorIndex][removeIndex] / (NumStates - 1);
newProbIndex++;
}
}
newVectorIndex++;
}
}
TransitionMatrix = newTransitionMatrix;
NumStates -= 1;
StateNames.Remove(state);
// If we just removed the current state:
if (state.Equals(currentState))
{
// Force transition to first available state:
SetCurrentState(StateNames[0]);
}
}