本文整理汇总了C#中System.Threading.SemaphoreSlim类的典型用法代码示例。如果您正苦于以下问题:C# SemaphoreSlim类的具体用法?C# SemaphoreSlim怎么用?C# SemaphoreSlim使用的例子?那么恭喜您, 这里精选的类代码示例或许可以为您提供帮助。
SemaphoreSlim类属于System.Threading命名空间,在下文中一共展示了SemaphoreSlim类的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: Main
//引入命名空间
using System;
using System.Threading;
using System.Threading.Tasks;
public class Example
{
private static SemaphoreSlim semaphore;
// A padding interval to make the output more orderly.
private static int padding;
public static void Main()
{
// Create the semaphore.
semaphore = new SemaphoreSlim(0, 3);
Console.WriteLine("{0} tasks can enter the semaphore.",
semaphore.CurrentCount);
Task[] tasks = new Task[5];
// Create and start five numbered tasks.
for(int i = 0; i <= 4; i++)
{
tasks[i] = Task.Run( () => {
// Each task begins by requesting the semaphore.
Console.WriteLine("Task {0} begins and waits for the semaphore.",
Task.CurrentId);
semaphore.Wait();
Interlocked.Add(ref padding, 100);
Console.WriteLine("Task {0} enters the semaphore.", Task.CurrentId);
// The task just sleeps for 1+ seconds.
Thread.Sleep(1000 + padding);
Console.WriteLine("Task {0} releases the semaphore; previous count: {1}.",
Task.CurrentId, semaphore.Release()); } );
}
// Wait for half a second, to allow all the tasks to start and block.
Thread.Sleep(500);
// Restore the semaphore count to its maximum value.
Console.Write("Main thread calls Release(3) --> ");
semaphore.Release(3);
Console.WriteLine("{0} tasks can enter the semaphore.",
semaphore.CurrentCount);
// Main thread waits for the tasks to complete.
Task.WaitAll(tasks);
Console.WriteLine("Main thread exits.");
}
}
输出:
0 tasks can enter the semaphore. Task 1 begins and waits for the semaphore. Task 5 begins and waits for the semaphore. Task 2 begins and waits for the semaphore. Task 4 begins and waits for the semaphore. Task 3 begins and waits for the semaphore. Main thread calls Release(3) --> 3 tasks can enter the semaphore. Task 4 enters the semaphore. Task 1 enters the semaphore. Task 3 enters the semaphore. Task 4 releases the semaphore; previous count: 0. Task 2 enters the semaphore. Task 1 releases the semaphore; previous count: 0. Task 3 releases the semaphore; previous count: 0. Task 5 enters the semaphore. Task 2 releases the semaphore; previous count: 1. Task 5 releases the semaphore; previous count: 2. Main thread exits.