本文整理汇总了C++中strArray::push_back方法的典型用法代码示例。如果您正苦于以下问题：C++ strArray::push_back方法的具体用法？C++ strArray::push_back怎么用？C++ strArray::push_back使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类strArray的用法示例。
在下文中一共展示了strArray::push_back方法的6个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: split
// string toolkit
static inline void split(std::string src, const char* token, strArray& vect)
{
int nend=0;
int nbegin=0;
while(nend != -1)
{
nend = src.find(token, nbegin);
if(nend == -1)
vect.push_back(src.substr(nbegin, src.length()-nbegin));
else
vect.push_back(src.substr(nbegin, nend-nbegin));
nbegin = nend + strlen(token);
}
}示例2: split
// string toolkit
static inline void split(const std::string& src, const std::string& token, strArray& vect)
{
size_t nend = 0;
size_t nbegin = 0;
size_t tokenSize = token.size();
while(nend != std::string::npos)
{
nend = src.find(token, nbegin);
if(nend == std::string::npos)
vect.push_back(src.substr(nbegin, src.length()-nbegin));
else
vect.push_back(src.substr(nbegin, nend-nbegin));
nbegin = nend + tokenSize;
}
}示例3: mult
void mult(strArray &a, strArray &b)
{
strArray c(a); a.clear();
for (int i = 0; i < c.size(); i ++)
for (int j = 0; j < b.size(); j ++)
a.push_back(c[i] + b[j]);
};示例4: split
// string toolkit
static KDvoid split ( std::string sString, const KDchar* szToken, strArray& vStrings )
{
KDint nEnd = 0;
KDint nBegin = 0;
while ( nEnd != -1 )
{
nEnd = sString.find ( szToken, nBegin );
if ( nEnd == -1 )
{
vStrings.push_back ( sString.substr ( nBegin, sString.length ( ) - nBegin ) );
}
else
{
vStrings.push_back ( sString.substr ( nBegin, nEnd - nBegin ) );
}
nBegin = nEnd + kdStrlen ( szToken );
}
}示例5: trans
bool trans(int l, int r, strArray &a)
{
int i = l, ope = 1, j;
strArray b, c, d;
string s;
a.clear();
if (l > r) {
a.push_back("");
return 1;
};
while (i <= r)
{
if (st[i] == '+')
{
if (ope) return 0;
ope = 1; ++i;
}
else {
if (!ope || (st[i] < 'a' || st[i] > 'z') && st[i] != '(') return 0;
b.clear(); b.push_back("");
while (i <= r && (st[i] >= 'a' && st[i] <= 'z' || st[i] == '('))
{
if (st[i] == '(')
{
if (!findEnd(i, j, r)) return 0;
if (!trans(i + 1, j - 1, c)) return 0;
i = j + 1;
}
else {
s = "";
while (i <= r && st[i] >= 'a' && st[i] <= 'z') s += st[i ++];
c.clear(); c.push_back(s);
};
if (c.empty()) return 0;
mult(b, c);
};
if (b.size() == 1 && b[0] == "") continue;
add(a, b); ope = 0;
};
};
if (ope && !a.empty()) return 0;
return 1;
};示例6: add
void add(strArray &a, const strArray &b)
{
for (int i = 0; i < b.size(); i ++)
a.push_back(b[i]);
};