本文整理汇总了C++中seg::contains方法的典型用法代码示例。如果您正苦于以下问题：C++ seg::contains方法的具体用法？C++ seg::contains怎么用？C++ seg::contains使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类seg的用法示例。
在下文中一共展示了seg::contains方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: tDir
int
seg::
contains ( const seg& segIn ) const
{
// TODO: Remove direction vector normalization?? User's responsibility???
vec3 tDir ( segIn.dir );
tDir.normalize ();
// vec3 endPt = segIn.pos + tDir * segIn.length;
vec3 endPt ( tDir );
endPt *= segIn.length;
endPt += segIn.pos;
int c1 = contains ( segIn.pos );
int c2 = contains ( endPt );
if ( c1 )
{
if ( c2 )
return containsResult::AllIn;
return containsResult::SomeIn;
}
if ( c2 )
return containsResult::SomeIn;
// OPTIMIZE: Expensive...
if ( segIn.contains ( pos ) )
return containsResult::SomeIn;
vec3 endPos = pos + dir * length;
if ( segIn.contains ( endPos ) )
return containsResult::SomeIn;
return containsResult::NoneIn;
}示例2: contains
// OPTIMIZE: This is a HUGE/heavyweight function. Probably several ways to optimize it.
int
sphere::
contains ( const seg& segIn ) const
{
vec3 pos;
vec3 dir;
ValueType len;
segIn.get ( pos, dir, len );
dir.normalize ();
vec3 endPos = pos + dir * len;
// The segment begin and endpoint might lie in the sphere.
int c1 = contains ( pos );
int c2 = contains ( endPos );
if ( c1 )
{
if ( c2 )
return containsResult::AllIn | containsResult::SomeIn;
return containsResult::SomeIn;
}
if ( c2 )
{
return containsResult::SomeIn;
}
ValueType a = dir.dot ( dir );
//ValueType a = dir.vec[0] * dir.vec[0] + dir.vec[1] * dir.vec[1] + dir.vec[2] * dir.vec[2];
ValueType b = static_cast< ValueType > ( 2.0 ) * dir.vec[0] * ( pos.vec[0] - center.vec[0] ) +
static_cast< ValueType > ( 2.0 ) * dir.vec[1] * ( pos.vec[1] - center.vec[1] ) +
static_cast< ValueType > ( 2.0 ) * dir.vec[2] * ( pos.vec[2] - center.vec[2] );
ValueType tx = pos.vec[0] - center.vec[0];
ValueType ty = pos.vec[1] - center.vec[1];
ValueType tz = pos.vec[2] - center.vec[2];
ValueType c = tx * tx + ty * ty + tz * tz - radius * radius;
//ValueType c = ( pos.vec[0] - center.vec[0] ) * ( pos.vec[0] - center.vec[0] ) +
// ( pos.vec[1] - center.vec[1] ) * ( pos.vec[0] - center.vec[0] ) +
// ( pos.vec[0] - center.vec[0] ) * ( pos.vec[0] - center.vec[0] ) -
// radius * radius;
// Check the discriminant to see if there are any solutions.
ValueType discriminant = b * b - static_cast< ValueType > ( 4.0 ) * a * c;
if ( discriminant < TraitType::zeroVal )
{
// No solutions --> no intersections.
return containsResult::NoneIn;
}
ValueType twoA = static_cast< ValueType > ( 2.0 ) * a;
if ( discriminant == TraitType::zeroVal )
{
// One intersection. Segment is tangential.
ValueType t1 = -b / twoA;
vec3 ip1 = pos + dir * t1;
return segIn.contains ( ip1 );
}
// Two intersections.
ValueType t1 = ( -b + TraitType::sqrt ( discriminant ) ) / twoA;
ValueType t2 = ( -b - TraitType::sqrt ( discriminant ) ) / twoA;
vec3 ip1 = pos + dir * t1;
vec3 ip2 = pos + dir * t2;
if ( segIn.contains ( ip1 ) || segIn.contains ( ip2 ) )
return containsResult::SomeIn;
else
return containsResult::NoneIn;
}