本文整理汇总了C++中ofPixels_::rotate90方法的典型用法代码示例。如果您正苦于以下问题：C++ ofPixels_::rotate90方法的具体用法？C++ ofPixels_::rotate90怎么用？C++ ofPixels_::rotate90使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类ofPixels_的用法示例。
在下文中一共展示了ofPixels_::rotate90方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: channelsFromPixelFormat
void ofPixels_<PixelType>::rotate90To(ofPixels_<PixelType> & dst, int nClockwiseRotations) const{
int channels = channelsFromPixelFormat(pixelFormat);
if (bAllocated == false || channels==0){
return;
}
if(&dst == this){
dst.rotate90(nClockwiseRotations);
return;
}
// first, figure out which type of rotation we have
int rotation = nClockwiseRotations;
while (rotation < 0){
rotation+=4;
}
rotation %= 4;
// if it's 0, just make a copy. if it's 2, do it by a mirror operation.
if (rotation == 0) {
dst = *this;
return;
// do nothing!
} else if (rotation == 2) {
mirrorTo(dst, true, true);
return;
}
// otherwise, we will need to do some new allocaiton.
dst.allocate(height,width,getImageType());
int strideSrc = width * channels;
int strideDst = dst.width * channels;
if(rotation == 1){
PixelType * srcPixels = pixels;
PixelType * startPixels = dst.getData() + strideDst;
for (int i = 0; i < height; ++i){
startPixels -= channels;
PixelType * dstPixels = startPixels;
for (int j = 0; j < width; ++j){
for (int k = 0; k < channels; ++k){
dstPixels[k] = srcPixels[k];
}
srcPixels += channels;
dstPixels += strideDst;
}
}
} else if(rotation == 3){
PixelType * dstPixels = dst.pixels;
PixelType * startPixels = pixels + strideSrc;
for (int i = 0; i < dst.height; ++i){
startPixels -= channels;
PixelType * srcPixels = startPixels;
for (int j = 0; j < dst.width; ++j){
for (int k = 0; k < channels; ++k){
dstPixels[k] = srcPixels[k];
}
srcPixels += strideSrc;
dstPixels += channels;
}
}
}
}