本文整理汇总了C++中nsDataHashtable::Count方法的典型用法代码示例。如果您正苦于以下问题：C++ nsDataHashtable::Count方法的具体用法？C++ nsDataHashtable::Count怎么用？C++ nsDataHashtable::Count使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类nsDataHashtable的用法示例。
在下文中一共展示了nsDataHashtable::Count方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: key
void
DottedCornerFinder::FindBestOverlap(Float aMinR, Float aMinBorderRadius,
Float aMaxBorderRadius)
{
// If overlap is not calculateable, find it with binary search,
// such that there exists i that C_i == C_n with the given overlap.
FourFloats key(aMinR, mMaxR,
aMinBorderRadius, aMaxBorderRadius);
BestOverlap best;
if (DottedCornerCache.Get(key, &best)) {
mCount = best.count;
mBestOverlap = best.overlap;
return;
}
Float lower = 0.0f;
Float upper = 0.5f;
// Start from lower bound to find the minimum number of circles.
Float overlap = 0.0f;
mBestOverlap = overlap;
size_t targetCount = 0;
const Float OVERLAP_MARGIN = 0.1f;
for (size_t j = 0; j < MAX_LOOP; j++) {
Reset();
size_t count;
Float actualOverlap;
if (!GetCountAndLastOverlap(overlap, &count, &actualOverlap)) {
if (j == 0) {
mCount = mMaxCount;
break;
}
}
if (j == 0) {
if (count < 3 || (count == 3 && actualOverlap > 0.5f)) {
// |count == 3 && actualOverlap > 0.5f| means there could be
// a circle but it is too near from both ends.
//
// if actualOverlap == 0.0
// 1 2 3
// +-------+-------+-------+-------+
// | ##### | ***** | ##### | ##### |
// |#######|*******|#######|#######|
// |###+###|***+***|###+###|###+###|
// |# C_0 #|* C_1 *|# C_2 #|# C_n #|
// | ##### | ***** | ##### | ##### |
// +-------+-------+-------+-------+
// |
// V
// +-------+---+-------+---+-------+
// | ##### | | ##### | | ##### |
// |#######| |#######| |#######|
// |###+###| |###+###| |###+###| Find the best overlap to place
// |# C_0 #| |# C_1 #| |# C_n #| C_1 at the middle of them
// | ##### | | ##### | | ##### |
// +-------+---+-------+---|-------+
//
// if actualOverlap == 0.5
// 1 2 3
// +-------+-------+-------+---+
// | ##### | ***** | ##### |## |
// |#######|*******|##### C_n #|
// |###+###|***+***|###+###+###|
// |# C_0 #|* C_1 *|# C_2 #|###|
// | ##### | ***** | ##### |## |
// +-------+-------+-------+---+
// |
// V
// +-------+-+-------+-+-------+
// | ##### | | ##### | | ##### |
// |#######| |#######| |#######|
// |###+###| |###+###| |###+###| Even if we place C_1 at the middle
// |# C_0 #| |# C_1 #| |# C_n #| of them, it's too near from them
// | ##### | | ##### | | ##### |
// +-------+-+-------+-|-------+
// |
// V
// +-------+-----------+-------+
// | ##### | | ##### |
// |#######| |#######|
// |###+###| |###+###| Do not draw any circle
// |# C_0 #| |# C_n #|
// | ##### | | ##### |
// +-------+-----------+-------+
mCount = 0;
break;
}
// targetCount should be 2n, as we're searching C_1 to C_n.
//
// targetCount = 4
// mCount = 1
// 1 2 3 4
// +-------+-------+-------+-------+-------+
// | ##### | ***** | ##### | ***** | ##### |
// |#######|*******|#######|*******|#######|
// |###+###|***+***|###+###|***+***|###+###|
//.........这里部分代码省略.........