当前位置: 首页>>代码示例>>C++>>正文

C++ mat_ZZ_p::NumRows方法代码示例

本文整理汇总了C++中mat_ZZ_p::NumRows方法的典型用法代码示例。如果您正苦于以下问题：C++ mat_ZZ_p::NumRows方法的具体用法？C++ mat_ZZ_p::NumRows怎么用？C++ mat_ZZ_p::NumRows使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类mat_ZZ_p的用法示例。


在下文中一共展示了mat_ZZ_p::NumRows方法的15个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。

示例1: mul_aux

void mul_aux(mat_ZZ_p& X, const mat_ZZ_p& A, const mat_ZZ_p& B)  
{  
   long n = A.NumRows();  
   long l = A.NumCols();  
   long m = B.NumCols();  
  
   if (l != B.NumRows())  
      Error("matrix mul: dimension mismatch");  
  
   X.SetDims(n, m);  
  
   long i, j, k;  
   ZZ acc, tmp;  
  
   for (i = 1; i <= n; i++) {  
      for (j = 1; j <= m; j++) {  
         clear(acc);  
         for(k = 1; k <= l; k++) {  
            mul(tmp, rep(A(i,k)), rep(B(k,j)));  
            add(acc, acc, tmp);  
         }  
         conv(X(i,j), acc);  
      }  
   }  
}
开发者ID:av-elier，项目名称:fast-exponentiation-algs，代码行数:25，代码来源:mat_ZZ_p.c

示例2: power

void power(mat_ZZ_p& X, const mat_ZZ_p& A, const ZZ& e)
{
   if (A.NumRows() != A.NumCols()) Error("power: non-square matrix");

   if (e == 0) {
      ident(X, A.NumRows());
      return;
   }

   mat_ZZ_p T1, T2;
   long i, k;

   k = NumBits(e);
   T1 = A;

   for (i = k-2; i >= 0; i--) {
      sqr(T2, T1);
      if (bit(e, i))
         mul(T1, T2, A);
      else
         T1 = T2;
   }

   if (e < 0)
      inv(X, T1);
   else
      X = T1;
}
开发者ID:av-elier，项目名称:fast-exponentiation-algs，代码行数:28，代码来源:mat_ZZ_p.c

示例3: mul

void mul(mat_ZZ_p& X, const mat_ZZ_p& A, const mat_ZZ_p& B)
{
   long n = A.NumRows();
   long l = A.NumCols();
   long m = B.NumCols();

   if (l != B.NumRows()) LogicError("matrix mul: dimension mismatch");

   if (NTL_USE_MM_MATMUL && n >= 24 && l >= 24 && m >= 24) 
      multi_modular_mul(X, A, B);
   else
      plain_mul(X, A, B);
}
开发者ID:tell，项目名称:ntl-unix，代码行数:13，代码来源:mat_ZZ_p.cpp

示例4: sub

void sub(mat_ZZ_p& X, const mat_ZZ_p& A, const mat_ZZ_p& B)  
{  
   long n = A.NumRows();  
   long m = A.NumCols();  
  
   if (B.NumRows() != n || B.NumCols() != m)  
      Error("matrix sub: dimension mismatch");  
  
   X.SetDims(n, m);  
  
   long i, j;  
   for (i = 1; i <= n; i++)  
      for (j = 1; j <= m; j++)  
         sub(X(i,j), A(i,j), B(i,j));  
}
开发者ID:av-elier，项目名称:fast-exponentiation-algs，代码行数:15，代码来源:mat_ZZ_p.c

示例5: transpose

void transpose(mat_ZZ_p& X, const mat_ZZ_p& A)
{
   long n = A.NumRows();
   long m = A.NumCols();

   long i, j;

   if (&X == & A) {
      if (n == m)
         for (i = 1; i <= n; i++)
            for (j = i+1; j <= n; j++)
               swap(X(i, j), X(j, i));
      else {
         mat_ZZ_p tmp;
         tmp.SetDims(m, n);
         for (i = 1; i <= n; i++)
            for (j = 1; j <= m; j++)
               tmp(j, i) = A(i, j);
         X.kill();
         X = tmp;
      }
   }
   else {
      X.SetDims(m, n);
      for (i = 1; i <= n; i++)
         for (j = 1; j <= m; j++)
            X(j, i) = A(i, j);
   }
}
开发者ID:av-elier，项目名称:fast-exponentiation-algs，代码行数:29，代码来源:mat_ZZ_p.c

示例6: clear

void clear(mat_ZZ_p& x)
{
   long n = x.NumRows();
   long i;
   for (i = 0; i < n; i++)
      clear(x[i]);
}
开发者ID:av-elier，项目名称:fast-exponentiation-algs，代码行数:7，代码来源:mat_ZZ_p.c

示例7: to_mat_ZZ_p_crt_rep

void to_mat_ZZ_p_crt_rep(mat_ZZ_p_crt_rep& X, const mat_ZZ_p& A)
{
   long n = A.NumRows();
   long m = A.NumCols();

   const MatPrime_crt_helper& H = get_MatPrime_crt_helper_info();
   long nprimes = H.GetNumPrimes();

   if (NTL_OVERFLOW(nprimes, CRT_BLK, 0))
      ResourceError("overflow"); // this is pretty academic

   X.rep.SetLength(nprimes);
   for (long k = 0; k < nprimes; k++) X.rep[k].SetDims(n, m);

   ZZ_pContext context;
   context.save();


   bool seq = (double(n)*double(m)*H.GetCost() < PAR_THRESH);

   // FIXME: right now, we just partition the rows, but if
   // #cols > #rows, we should perhaps partition the cols
   NTL_GEXEC_RANGE(seq, n, first, last)
   NTL_IMPORT(n)
   NTL_IMPORT(m)
   NTL_IMPORT(nprimes)

   context.restore();

   MatPrime_crt_helper_scratch scratch;
   Vec<MatPrime_residue_t> remainders_store;
   remainders_store.SetLength(nprimes*CRT_BLK);
   MatPrime_residue_t *remainders = remainders_store.elts();

   for (long i = first; i < last; i++) {
      const ZZ_p *a = A[i].elts();

      long jj = 0; 
      for (; jj <= m-CRT_BLK; jj += CRT_BLK) {
         for (long j = 0; j < CRT_BLK; j++)
            reduce(H, rep(a[jj+j]), remainders + j*nprimes, scratch);
         for (long k = 0; k < nprimes; k++) {
            MatPrime_residue_t *x = X.rep[k][i].elts();
            for (long j = 0; j < CRT_BLK; j++)
               x[jj+j] = remainders[j*nprimes+k];
         }
      }
      if (jj < m) {
         for (long j = 0; j < m-jj; j++)
            reduce(H, rep(a[jj+j]), remainders + j*nprimes, scratch);
         for (long k = 0; k < nprimes; k++) {
            MatPrime_residue_t *x = X.rep[k][i].elts();
            for (long j = 0; j < m-jj; j++)
               x[jj+j] = remainders[j*nprimes+k];
         }
      }
   }

   NTL_GEXEC_RANGE_END
}
开发者ID:tell，项目名称:ntl-unix，代码行数:60，代码来源:mat_ZZ_p.cpp

示例8: add

NTL_START_IMPL

  
void add(mat_ZZ_p& X, const mat_ZZ_p& A, const mat_ZZ_p& B)  
{  
   long n = A.NumRows();  
   long m = A.NumCols();  
  
   if (B.NumRows() != n || B.NumCols() != m)   
      LogicError("matrix add: dimension mismatch");  
  
   X.SetDims(n, m);  
  
   long i, j;  
   for (i = 1; i <= n; i++)   
      for (j = 1; j <= m; j++)  
         add(X(i,j), A(i,j), B(i,j));  
}
开发者ID:axelexic，项目名称:NTL，代码行数:18，代码来源:mat_ZZ_p.c

示例9: plain_mul_transpose_aux

void plain_mul_transpose_aux(mat_ZZ_p& X, const mat_ZZ_p& A, const mat_ZZ_p& B)  
{  
   long n = A.NumRows();  
   long l = A.NumCols();  
   long m = B.NumRows();  
  
   if (l != B.NumCols())  
      LogicError("matrix mul: dimension mismatch");  
  
   X.SetDims(n, m);  

   ZZ_pContext context;
   context.save();

   long sz = ZZ_p::ModulusSize();
   bool seq = (double(n)*double(l)*double(m)*double(sz)*double(sz) < PAR_THRESH);
  
   NTL_GEXEC_RANGE(seq, m, first, last)
   NTL_IMPORT(n)
   NTL_IMPORT(l)
   NTL_IMPORT(m)

   context.restore();

   long i, j, k;  
   ZZ acc, tmp;  

   for (j = first; j < last; j++) {
      const ZZ_p *B_col = B[j].elts();

      for (i = 0; i < n; i++) {
         clear(acc);
         for (k = 0; k < l; k++) {
            mul(tmp, rep(A[i][k]), rep(B_col[k]));
            add(acc, acc, tmp);
         }
         conv(X[i][j], acc);
      }
   }

   NTL_GEXEC_RANGE_END
}
开发者ID:tell，项目名称:ntl-unix，代码行数:42，代码来源:mat_ZZ_p.cpp

示例10: IsZero

long IsZero(const mat_ZZ_p& a)
{
   long n = a.NumRows();
   long i;

   for (i = 0; i < n; i++)
      if (!IsZero(a[i]))
         return 0;

   return 1;
}
开发者ID:av-elier，项目名称:fast-exponentiation-algs，代码行数:11，代码来源:mat_ZZ_p.c

示例11: negate

void negate(mat_ZZ_p& X, const mat_ZZ_p& A)  
{  
   long n = A.NumRows();  
   long m = A.NumCols();  
  
  
   X.SetDims(n, m);  
  
   long i, j;  
   for (i = 1; i <= n; i++)  
      for (j = 1; j <= m; j++)  
         negate(X(i,j), A(i,j));  
}
开发者ID:av-elier，项目名称:fast-exponentiation-algs，代码行数:13，代码来源:mat_ZZ_p.c

示例12: mul

void mul(mat_ZZ_p& X, const mat_ZZ_p& A, long b_in)
{
   NTL_ZZ_pRegister(b);
   b = b_in;
   long n = A.NumRows();
   long m = A.NumCols();

   X.SetDims(n, m);

   long i, j;
   for (i = 0; i < n; i++)
      for (j = 0; j < m; j++)
         mul(X[i][j], A[i][j], b);
}
开发者ID:av-elier，项目名称:fast-exponentiation-algs，代码行数:14，代码来源:mat_ZZ_p.c

示例13: multi_modular_mul

void multi_modular_mul(mat_ZZ_p& X, const mat_ZZ_p& A, const mat_ZZ_p& B)
{
   long l = A.NumCols();

   if (l != B.NumRows())
      LogicError("matrix mul: dimension mismatch");  

   if (l > NTL_MatPrimeLimit)
      ResourceError("matrix mul: dimension too large");

   mat_ZZ_p_crt_rep x, a, b;

   to_mat_ZZ_p_crt_rep(a, A);
   to_mat_ZZ_p_crt_rep(b, B);
   mul(x, a, b);
   from_mat_ZZ_p_crt_rep(x, X);
}
开发者ID:tell，项目名称:ntl-unix，代码行数:17，代码来源:mat_ZZ_p.cpp

示例14: IsDiag

long IsDiag(const mat_ZZ_p& A, long n, const ZZ_p& d)
{
   if (A.NumRows() != n || A.NumCols() != n)
      return 0;

   long i, j;

   for (i = 1; i <= n; i++)
      for (j = 1; j <= n; j++)
         if (i != j) {
            if (!IsZero(A(i, j))) return 0;
         }
         else {
            if (A(i, j) != d) return 0;
         }

   return 1;
}
开发者ID:av-elier，项目名称:fast-exponentiation-algs，代码行数:18，代码来源:mat_ZZ_p.c

示例15: IsIdent

long IsIdent(const mat_ZZ_p& A, long n)
{
   if (A.NumRows() != n || A.NumCols() != n)
      return 0;

   long i, j;

   for (i = 1; i <= n; i++)
      for (j = 1; j <= n; j++)
         if (i != j) {
            if (!IsZero(A(i, j))) return 0;
         }
         else {
            if (!IsOne(A(i, j))) return 0;
         }

   return 1;
}
开发者ID:av-elier，项目名称:fast-exponentiation-algs，代码行数:18，代码来源:mat_ZZ_p.c


注：本文中的mat_ZZ_p::NumRows方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台，相关代码片段筛选自各路编程大神贡献的开源项目，源码版权归原作者所有，传播和使用请参考对应项目的License；未经允许，请勿转载。