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C++ interval::intersect方法代码示例

本文整理汇总了C++中interval::intersect方法的典型用法代码示例。如果您正苦于以下问题:C++ interval::intersect方法的具体用法?C++ interval::intersect怎么用?C++ interval::intersect使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在interval的用法示例。


在下文中一共展示了interval::intersect方法的7个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。

示例1: sqr_inverse

// FIXME It actually performs intersection which is inconsistent with intersect
bool sqr_inverse(interval& z, interval& x, interval& gap) {

	bool has_gap = false;

	const interval x_1 = sqrt(z);

	const interval x_2 = -x_1;

	interval x_image;

	if (disjoint(x, x_2)) {

		x_image = x_1;
	}
	else if (disjoint(x, x_1)) {

		x_image = x_2;
	}
	else {

		gap = interval(x_2.sup(), x_1.inf());

		has_gap = gap.diameter() > IMPROVEMENT_TOL; // FIXME GAP_SQRT_TOL ?

		x_image = hull_of(x_1, x_2);
	}

	x.intersect(x_image);

	z.intersect(sqr(x));

	return has_gap;
}
开发者ID:baharev,项目名称:old_sandbox,代码行数:34,代码来源:interval.cpp

示例2: addition_inverse

void addition_inverse(interval& z, interval& x, interval& y) {

	x.intersect(z-y);

	y.intersect(z-x);

	z.intersect(x+y);
}
开发者ID:baharev,项目名称:old_sandbox,代码行数:8,代码来源:interval.cpp

示例3: division_inverse

bool division_inverse(interval& z, interval& x, interval& y, interval& gap) {

	// z = x/y --> x = z*y
	x.intersect(z*y);

	// y = x/z
	bool has_gap = extended_division(x, z, y, gap);

	z.intersect(x/y);

	return has_gap;
}
开发者ID:baharev,项目名称:old_sandbox,代码行数:12,代码来源:interval.cpp

示例4: extended_division

// Returns true and sets gap if a gap is generated, otherwise gap is undefined
bool extended_division(const interval& x, const interval& y, interval& z, interval& gap) {

	gap = interval();

	if (z.is_narrow()) { // if narrow, don't do anything
		// TODO Actually, feasibility could be checked
		return false;
	}

	if (!y.contains(0)) {  // trivial case

		z.intersect(x/y);

		return false;
	}
	// y.contains(0)==true

	if (x.contains(0)) {  // no progress case

		return false;
	}
	// (!x.contains(0) && y.contains(0)) == true

	if (y.inf()==0 && y.sup()==0) {  // undefined case
		// FIXME Is it safe to declare it infeasible? Or should we just signal no progress?
		//ASSERT2(false, "undefined result; x, z: "<<x<<", "<<z);
		throw infeasible_problem();
	}

	return true_extended_division(x, y, z, gap);
}
开发者ID:baharev,项目名称:old_sandbox,代码行数:32,代码来源:interval.cpp

示例5: propagate_mult

// z = x*y
void propagate_mult(interval& z, interval& x, interval& y) {
// TODO Eliminate propagate_mult, only used by envelopes
//	if (!x.contains(0)) { // y = z/x
//
//		y.intersect(z/x);
//	}

	interval gap;

	extended_division(z, x, y, gap);

//	if (!y.contains(0)) {  // x = z/y
//
//		x.intersect(z/y);
//	}

	extended_division(z, y, x, gap);

	// z = x*y
	z.intersect(x*y);
}
开发者ID:baharev,项目名称:old_sandbox,代码行数:22,代码来源:interval.cpp

示例6: less_than_or_equal_to

void interval::less_than_or_equal_to(interval& rhs) {

	ASSERT2(rhs.lb <= rhs.ub, rhs);
	ASSERT2(lb <= ub, *this);

	//  this  <=  rhs
	// [a, b] <= [c, d]

	const double a = lb;

	const double d = rhs.ub;

	if (a > d) {

		throw infeasible_problem();
	}

	intersect(a, d); // b <= d; b is modified appropriately

	rhs.intersect(a, d); // a <= c; c is modified appropriately
}
开发者ID:baharev,项目名称:old_sandbox,代码行数:21,代码来源:interval.cpp

示例7: log_inverse

void log_inverse(interval& z, interval& x) {

	x.intersect(exp(z));

	z.intersect(log(x));
}
开发者ID:baharev,项目名称:old_sandbox,代码行数:6,代码来源:interval.cpp


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