本文整理汇总了C++中expr::is_numerical方法的典型用法代码示例。如果您正苦于以下问题：C++ expr::is_numerical方法的具体用法？C++ expr::is_numerical怎么用？C++ expr::is_numerical使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类expr的用法示例。
在下文中一共展示了expr::is_numerical方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: ASSERT
/*!\brief Expand an expression of the form scale * addition
*
* Provided \c scale is not a sum, expand the expression
* <tt>scale * (+ c a1 ...)</tt> into <tt>scale * c + scale * a1 + ...</tt>.
*/
ptr<const sum>
expand_prod_sum( const expr &scale, const sum &addition )
{
ASSERT( addition.is_expanded() && ! scale.is_a< sum >() );
if( scale.is_numerical() )
{ // easy case -> sum::sca does the work
const number &ns = scale.as_a< numerical >()->get();
ptr< const sum > ret
= ns.unit()
? &addition
: sum::sca( ns, addition );
ret->basic::expand();
return ret;
}
// hard case : distribute term by term
number coef = 0;
ptr< const prod > scale_prod = scale.get()->as_prod();
// addition.size() for nsp * addition
// + 1 for scale_prod * addition.coef()
container::ptr_unsafe_vector< const prod > seq ( addition.size() + 1 );
{ // coefficient handling
const prod* ph = scale_prod.get();
// cannot be numerical since [scale_prod] isn't
seq.push_back( prod::handle::sca( ph, addition.coef() ) );
}
for(const prod* p : addition)
{
ASSERT( p );
const expr ex = prod::mul( *p, *scale_prod );
// seams reasonable here
ASSERT( ! ex.is_a< sum >() );
if( ex.is_numerical() )
coef += ex.as_a< numerical >()->get();
else
seq.push_back( ex.get()->as_prod() );
}
expand_detail::sort( seq.begin(), seq.end() );
ptr< const sum > ret = sum::from_sorted_prod_range( coef, seq.begin(), seq.end() );
ret->basic::expand(); // mark expanded
return ret;
}