本文整理汇总了C++中dictionary::remove方法的典型用法代码示例。如果您正苦于以下问题：C++ dictionary::remove方法的具体用法？C++ dictionary::remove怎么用？C++ dictionary::remove使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类dictionary的用法示例。
在下文中一共展示了dictionary::remove方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: alreadyMerged
void Foam::multiSolver::buildDictionary
(
dictionary& outputDict,
const dictionary& inputDict,
const word& solverDomainName
)
{
outputDict.remove("sameAs");
outputDict.remove("multiLoad");
wordList alreadyMerged(0);
wordList mergeMe(0);
if (inputDict.found("default"))
{
if (outputDict.found("multiLoad"))
{
mergeMe = wordList(outputDict.lookup("multiLoad"));
outputDict.remove("multiLoad");
}
if (outputDict.found("sameAs"))
{
label newIndex(mergeMe.size());
mergeMe.setSize(newIndex + 1);
mergeMe[newIndex] = word(outputDict.lookup("sameAs"));
outputDict.remove("sameAs");
}
}
// We load solverDomain last, but we need its sameAs / multiLoad now
if (inputDict.found(solverDomainName))
{
const dictionary& solverDict(inputDict.subDict(solverDomainName));
if (solverDict.found("multiLoad"))
{
mergeMe.append(wordList(solverDict.lookup("multiLoad")));
}
if (solverDict.found("sameAs"))
{
label newIndex(mergeMe.size());
mergeMe.setSize(newIndex + 1);
mergeMe[newIndex] = word(solverDict.lookup("sameAs"));
}
}
label mergeI(-1);
while ((mergeI + 1) < mergeMe.size())
{
mergeI++;
bool skipMe(false);
forAll(alreadyMerged, alreadyI)
{
if (mergeMe[mergeI] == alreadyMerged[alreadyI])
{
skipMe = true;
break;
}
}
if (skipMe)
{
break;
}
outputDict.merge(inputDict.subDict(mergeMe[mergeI]));
// Add to alreadyMerged
label mergedIndex(alreadyMerged.size());
alreadyMerged.setSize(mergedIndex + 1);
alreadyMerged[mergedIndex] = mergeMe[mergeI];
// Recursive search
if (outputDict.found("multiLoad"))
{
mergeMe.append(wordList(outputDict.lookup("multiLoad")));
outputDict.remove("multiLoad");
}
if (outputDict.found("sameAs"))
{
label newMergeMeIndex(mergeMe.size());
mergeMe.setSize(newMergeMeIndex + 1);
mergeMe[newMergeMeIndex] = word(outputDict.lookup("sameAs"));
outputDict.remove("sameAs");
}
}
// Merge the solverDomain name, even if it already has merged
if (inputDict.found(solverDomainName))
{
outputDict.merge(inputDict.subDict(solverDomainName));
// These have been handled already
outputDict.remove("sameAs");
outputDict.remove("multiLoad");
}
}