当前位置: 首页>>代码示例>>C++>>正文


C++ default_ops::eval_divide方法代码示例

本文整理汇总了C++中default_ops::eval_divide方法的典型用法代码示例。如果您正苦于以下问题:C++ default_ops::eval_divide方法的具体用法?C++ default_ops::eval_divide怎么用?C++ default_ops::eval_divide使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在default_ops的用法示例。


在下文中一共展示了default_ops::eval_divide方法的7个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。

示例1:

BOOST_MP_FORCEINLINE typename enable_if<is_compatible_arithmetic_type<V, number<B, et_off> >, number<B, et_off> >::type
   operator / (number<B, et_off>&& a, const V& b)
{
   using default_ops::eval_divide;
   eval_divide(a.backend(), number<B, et_off>::canonical_value(b));
   return static_cast<number<B, et_off>&&>(a);
}
开发者ID:AsherBond,项目名称:PDAL,代码行数:7,代码来源:no_et_ops.hpp

示例2:

BOOST_MP_FORCEINLINE number<B, et_off> operator / (number<B, et_off>&& a, const number<B, et_off>& b)
{
   using default_ops::eval_divide;
   detail::scoped_default_precision<multiprecision::number<B, et_off> > precision_guard(a, b);
   eval_divide(a.backend(), b.backend());
   return static_cast<number<B, et_off>&&>(a);
}
开发者ID:betajippity,项目名称:Nuparu,代码行数:7,代码来源:no_et_ops.hpp

示例3: BOOST_MP_MOVE

BOOST_MP_FORCEINLINE number<B, et_off> operator / (const number<B, et_off>& a, const number<B, et_off>& b)
{
   number<B, et_off> result;
   using default_ops::eval_divide;
   eval_divide(result.backend(), a.backend(), b.backend());
   return BOOST_MP_MOVE(result);
}
开发者ID:AsherBond,项目名称:PDAL,代码行数:7,代码来源:no_et_ops.hpp

示例4: precision_guard

BOOST_MP_FORCEINLINE number<B, et_off> operator / (const number<B, et_off>& a, const number<B, et_off>& b)
{
   detail::scoped_default_precision<multiprecision::number<B, et_off> > precision_guard(a, b);
   number<B, et_off> result;
   using default_ops::eval_divide;
   eval_divide(result.backend(), a.backend(), b.backend());
   return result;
}
开发者ID:betajippity,项目名称:Nuparu,代码行数:8,代码来源:no_et_ops.hpp

示例5: generic_interconvert

void generic_interconvert(To& to, const From& from, const mpl::int_<number_kind_floating_point>& /*to_type*/, const mpl::int_<number_kind_rational>& /*from_type*/)
{
   typedef typename component_type<number<From> >::type   from_component_type;
   using default_ops::eval_divide;

   number<From> t(from);
   from_component_type n(numerator(t)), d(denominator(t));
   number<To> fn(n), fd(d);
   eval_divide(to, fn.backend(), fd.backend());
}
开发者ID:1ack,项目名称:Impala,代码行数:10,代码来源:generic_interconvert.hpp

示例6: convert_to_string

std::string convert_to_string(Backend b, std::streamsize digits, std::ios_base::fmtflags f)
{
   using default_ops::eval_log10;
   using default_ops::eval_floor;
   using default_ops::eval_pow;
   using default_ops::eval_convert_to;
   using default_ops::eval_multiply;
   using default_ops::eval_divide;
   using default_ops::eval_subtract;
   using default_ops::eval_fpclassify;

   typedef typename mpl::front<typename Backend::unsigned_types>::type ui_type;
   typedef typename Backend::exponent_type exponent_type;

   std::string result;
   bool iszero = false;
   bool isneg = false;
   exponent_type expon = 0;
   std::streamsize org_digits = digits;
   BOOST_ASSERT(digits > 0);

   int fpt = eval_fpclassify(b);

   if(fpt == (int)FP_ZERO)
   {
      result = "0";
      iszero = true;
   }
   else if(fpt == (int)FP_INFINITE)
   {
      if(b.compare(ui_type(0)) < 0)
         return "-inf";
      else
         return ((f & std::ios_base::showpos) == std::ios_base::showpos) ? "+inf" : "inf";
   }
   else if(fpt == (int)FP_NAN)
   {
      return "nan";
   }
   else
   {
      //
      // Start by figuring out the exponent:
      //
      isneg = b.compare(ui_type(0)) < 0;
      if(isneg)
         b.negate();
      Backend t;
      Backend ten;
      ten = ui_type(10);

      eval_log10(t, b);
      eval_floor(t, t);
      eval_convert_to(&expon, t);
      if(-expon > std::numeric_limits<number<Backend> >::max_exponent10 - 3)
      {
         int e = -expon / 2;
         Backend t2;
         eval_pow(t2, ten, e);
         eval_multiply(t, t2, b);
         eval_multiply(t, t2);
         if(expon & 1)
            eval_multiply(t, ten);
      }
      else
      {
         eval_pow(t, ten, -expon);
         eval_multiply(t, b);
      }
      //
      // Make sure we're between [1,10) and adjust if not:
      //
      if(t.compare(ui_type(1)) < 0)
      {
         eval_multiply(t, ui_type(10));
         --expon;
      }
      else if(t.compare(ui_type(10)) >= 0)
      {
         eval_divide(t, ui_type(10));
         ++expon;
      }
      Backend digit;
      ui_type cdigit;
      //
      // Adjust the number of digits required based on formatting options:
      //
      if(((f & std::ios_base::fixed) == std::ios_base::fixed) && (expon != -1))
         digits += expon + 1;
      if((f & std::ios_base::scientific) == std::ios_base::scientific)
         ++digits;
      //
      // Extract the digits one at a time:
      //
      for(unsigned i = 0; i < digits; ++i)
      {
         eval_floor(digit, t);
         eval_convert_to(&cdigit, digit);
         result += static_cast<char>('0' + cdigit);
         eval_subtract(t, digit);
//.........这里部分代码省略.........
开发者ID:13W,项目名称:icq-desktop,代码行数:101,代码来源:float_string_cvt.hpp

示例7: convert_from_string

void convert_from_string(Backend& b, const char* p)
{
   using default_ops::eval_multiply;
   using default_ops::eval_add;
   using default_ops::eval_pow;
   using default_ops::eval_divide;

   typedef typename mpl::front<typename Backend::unsigned_types>::type ui_type;
   b = ui_type(0);
   if(!p || (*p == 0))
      return;

   bool is_neg = false;
   bool is_neg_expon = false;
   static const ui_type ten = ui_type(10);
   typename Backend::exponent_type expon = 0;
   int digits_seen = 0;
   typedef std::numeric_limits<number<Backend, et_off> > limits;
   static const int max_digits = limits::is_specialized ? limits::max_digits10 + 1 : INT_MAX;

   if(*p == '+') ++p;
   else if(*p == '-')
   {
      is_neg = true;
      ++p;
   }
   if((std::strcmp(p, "nan") == 0) || (std::strcmp(p, "NaN") == 0) || (std::strcmp(p, "NAN") == 0))
   {
      eval_divide(b, ui_type(0));
      if(is_neg)
         b.negate();
      return;
   }
   if((std::strcmp(p, "inf") == 0) || (std::strcmp(p, "Inf") == 0) || (std::strcmp(p, "INF") == 0))
   {
      b = ui_type(1);
      eval_divide(b, ui_type(0));
      if(is_neg)
         b.negate();
      return;
   }
   //
   // Grab all the leading digits before the decimal point:
   //
   while(std::isdigit(*p))
   {
      eval_multiply(b, ten);
      eval_add(b, ui_type(*p - '0'));
      ++p;
      ++digits_seen;
   }
   if(*p == '.')
   {
      //
      // Grab everything after the point, stop when we've seen
      // enough digits, even if there are actually more available:
      //
      ++p;
      while(std::isdigit(*p))
      {
         eval_multiply(b, ten);
         eval_add(b, ui_type(*p - '0'));
         ++p;
         --expon;
         if(++digits_seen > max_digits)
            break;
      }
      while(std::isdigit(*p))
         ++p;
   }
   //
   // Parse the exponent:
   //
   if((*p == 'e') || (*p == 'E'))
   {
      ++p;
      if(*p == '+') ++p;
      else if(*p == '-')
      {
         is_neg_expon = true;
         ++p;
      }
      typename Backend::exponent_type e2 = 0;
      while(std::isdigit(*p))
      {
         e2 *= 10;
         e2 += (*p - '0');
         ++p;
      }
      if(is_neg_expon)
         e2 = -e2;
      expon += e2;
   }
   if(expon)
   {
      // Scale by 10^expon, note that 10^expon can be
      // outside the range of our number type, even though the
      // result is within range, if that looks likely, then split
      // the calculation in two:
      Backend t;
//.........这里部分代码省略.........
开发者ID:13W,项目名称:icq-desktop,代码行数:101,代码来源:float_string_cvt.hpp


注:本文中的default_ops::eval_divide方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。