本文整理汇总了C++中container_type::resize方法的典型用法代码示例。如果您正苦于以下问题：C++ container_type::resize方法的具体用法？C++ container_type::resize怎么用？C++ container_type::resize使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类container_type的用法示例。
在下文中一共展示了container_type::resize方法的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1:
void operator=(VecExpression<E> const& vec) {
E const& v = vec;
_data.resize(v.size());
for (size_type i = 0; i != v.size(); ++i) {
_data[i] = v[i];
}
}示例2: ts
/*
* Construction from triplets.
* This is the main workhorse of the data structure, taking an unordered (potentially uncompressed)
* vector of triplets and performing the required sorting to convert it into a sparse_bcsr ordering.
*
* This function DOES MODIFY the input triplet vector "ts" (by sorting)
*/
sparse_bcsr(const std::vector<triplet> & _ts) : _brows(0), _bcols(0), _zero(0)
{
std::vector<triplet> ts(_ts);
block_stride = BLOCK*BLOCK;
assert(ts.size() > 0 && "Doesn't support empty matrices (yet)");
//sort the triplets into bcsr order using the bcsr_compare struct
std::sort(ts.begin(), ts.end(), bcsr_compare());
size_type brows = std::get<0>(*ts.rbegin())/BLOCK+1;
brow_ptr.resize(brows+1, size_type(0));
size_type curr_brow = std::get<0>(ts[0])/BLOCK;
size_type curr_bcol = std::get<1>(ts[0])/BLOCK;
// count number of blocks (single pass thru tuples. saves mem alloc time from push_back calls)
size_type nblocks = 1;
for(size_type i=1; i<ts.size(); ++i) {
if(curr_brow == std::get<0>(ts[i])/BLOCK &&
curr_bcol == std::get<1>(ts[i])/BLOCK) {
}
else {
++nblocks;
}
curr_brow = std::get<0>(ts[i])/BLOCK;
curr_bcol = std::get<1>(ts[i])/BLOCK;
}
// resize storage containers
bcol_index.resize(nblocks, size_type(0));
data.resize(nblocks*block_stride, value_type(0));
//construct from triplets
curr_brow = std::get<0>(ts[0])/BLOCK;
curr_bcol = std::get<1>(ts[0])/BLOCK;
//_rows = std::get<0>(ts[0])+1;
//_cols = std::get<1>(ts[0])+1;
for(size_type r=0; r<=curr_brow; ++r) {
brow_ptr[r] = 0;
}
bcol_index[0] = curr_bcol;
data[index(0, std::get<0>(ts[0])%BLOCK, std::get<1>(ts[0])%BLOCK)] = std::get<2>(ts[0]);
size_type bidx = 0;
for(size_type idx=1; idx<ts.size(); ++idx) {
size_type I = std::get<0>(ts[idx])/BLOCK;
size_type J = std::get<1>(ts[idx])/BLOCK;
size_type i = std::get<0>(ts[idx])%BLOCK;
size_type j = std::get<1>(ts[idx])%BLOCK;
value_type val = std::get<2>(ts[idx]);
//keep track of number of brows, bcols.
// not yet sure if I should enforce matrix sizes to be multiples of BLOCK
_brows = (I+1)>_brows ? I+1 : _brows;
_bcols = (J+1)>_bcols ? J+1 : _bcols;
if(I==curr_brow && J==curr_bcol) {
data[index(bidx, i, j)] += val;
}
else {
++bidx;
if(curr_brow != I) {
for(size_type r=curr_brow+1; r<=I; ++r) {
brow_ptr[r] = bidx;
}
curr_brow = I;
}
curr_bcol = J;
bcol_index[bidx] = J;
data[index(bidx, i, j)] += val;
}
}
brow_ptr[_brows] = nblocks;
}示例3: resize
static void resize( const container_type &x , container_type &dxdt )
{
dxdt.resize( x.size1() , x.size2() );
}