本文整理汇总了C++中btDispatcher::needsResponse方法的典型用法代码示例。如果您正苦于以下问题:C++ btDispatcher::needsResponse方法的具体用法?C++ btDispatcher::needsResponse怎么用?C++ btDispatcher::needsResponse使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类btDispatcher
的用法示例。
在下文中一共展示了btDispatcher::needsResponse方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: needsCollision
virtual bool needsCollision(btBroadphaseProxy* proxy0) const
{
//don't collide with itself
if (proxy0->m_clientObject == m_me)
return false;
///don't do CCD when the collision filters are not matching
if (!ClosestConvexResultCallback::needsCollision(proxy0))
return false;
btCollisionObject* otherObj = (btCollisionObject*) proxy0->m_clientObject;
//call needsResponse, see http://code.google.com/p/bullet/issues/detail?id=179
if (m_dispatcher->needsResponse(m_me,otherObj))
{
///don't do CCD when there are already contact points (touching contact/penetration)
btAlignedObjectArray<btPersistentManifold*> manifoldArray;
btBroadphasePair* collisionPair = m_pairCache->findPair(m_me->getBroadphaseHandle(),proxy0);
if (collisionPair)
{
if (collisionPair->m_algorithm)
{
manifoldArray.resize(0);
collisionPair->m_algorithm->getAllContactManifolds(manifoldArray);
for (int j=0;j<manifoldArray.size();j++)
{
btPersistentManifold* manifold = manifoldArray[j];
if (manifold->getNumContacts()>0)
return false;
}
}
}
}
return true;
}