本文整理汇总了C++中boost::count_if方法的典型用法代码示例。如果您正苦于以下问题：C++ boost::count_if方法的具体用法？C++ boost::count_if怎么用？C++ boost::count_if使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类boost的用法示例。
在下文中一共展示了boost::count_if方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: print_accepted
void print_accepted(const util::NodeRange& nodes,
std::function<bool(Node, Node)> is_strong,
std::function<bool(Node)> is_root)
{
using util::fmt;
using std::endl;
using std::cout;
auto count_parents = [&](const auto N) {
using boost::count_if;
using common::pars;
auto has_n_parents = [&](auto node) {
auto is_accepted = [&](auto par) { return is_strong(par, node); };
return !is_root(node) && count_if(pars(node), is_accepted) == N;
};
return count_if(nodes, has_n_parents);
};
auto W = static_cast<floating_t>(nodes.size()) / 100.;
cout << "0 parents accepted: " << fmt(count_parents(0) / W) << "%" << endl;
cout << "1 parents accepted: " << fmt(count_parents(1) / W) << "%" << endl;
cout << "2 parents accepted: " << fmt(count_parents(2) / W) << "%" << endl;
cout << "3 parents accepted: " << fmt(count_parents(3) / W) << "%" << endl;
cout << "4 parents accepted: " << fmt(count_parents(4) / W) << "%" << endl;
}示例2: print_roots
void print_roots(const util::NodeRange& nodes,
std::function<bool(Node)> is_root)
{
using boost::count_if;
assert(nodes.size() > 0);
auto num_roots = count_if(nodes, is_root);
std::cout << " roots: ";
const auto pcnt = (num_roots * 100.) / nodes.size();
std::cout << num_roots << "(" << util::fmt(pcnt, 5) << "%)";
std::cout << std::endl;
}