本文整理汇总了C++中base_type::end方法的典型用法代码示例。如果您正苦于以下问题:C++ base_type::end方法的具体用法?C++ base_type::end怎么用?C++ base_type::end使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类base_type
的用法示例。
在下文中一共展示了base_type::end方法的9个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: end
typename cop<KeyT,DataT,CompareT,AllocT>::iterator
cop<KeyT,DataT,CompareT,AllocT>::subtract(const key_type& key)
{
iterator it_ = find(key);
if(it_ != end())
erase(it_);
return end();
}
示例2: return
const T & operator[] (const T &key) const {
typename base_type::const_iterator it;
it = base.find(key);
if (it == base.end()) {
return (base[key] = key);
}
return it->second;
}
示例3: begin
cop<KeyT,DataT,CompareT,AllocT>& cop<KeyT,DataT,CompareT,AllocT>
::keep_if(const property<value_type>& hasProperty)
{
iterator it = begin(), victim;
while(it != end())
if ( !hasProperty(*it) ) { victim = it++; erase(victim); } else ++it;
return *this;
}
示例4: size
bool operator== (const lazy_substring<T>& that) const
{
if (this == &that)
return true;
if (m_string == that.m_string)
return m_start == that.m_start and m_end == that.m_end;
return size() == that.size()
and std::equal(begin(), end(), that.begin());
}
示例5: lexicographical_compare
bool operator< (const lazy_substring<T>& that) const
{
if (this == &that)
return false;
return std::lexicographical_compare(
begin()
, end()
, that.begin()
, that.end()
);
}
示例6: const_reverse_iterator
template <typename Iter> inline typename range_base<Iter, std::bidirectional_iterator_tag>::const_reverse_iterator
range_base<Iter, std::bidirectional_iterator_tag>::rbegin() const {
return const_reverse_iterator(end());
}
示例7: contains
//JODO concept set
/// Checks if a key element is in the cop
bool contains(const KeyT& x)const { return !(find(x) == end()); }
示例8: append
Wave& append(const Wave& other)
{
base_type::insert(end(), other.begin(), other.end());
return *this;
}
示例9: string
string_type string(void) const
{ return string_type(begin(), end()); }