本文整理汇总了C++中VisualNode::hasSolvedChildren方法的典型用法代码示例。如果您正苦于以下问题：C++ VisualNode::hasSolvedChildren方法的具体用法？C++ VisualNode::hasSolvedChildren怎么用？C++ VisualNode::hasSolvedChildren使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类VisualNode的用法示例。
在下文中一共展示了VisualNode::hasSolvedChildren方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: compressInit
bool IcicleTreeCanvas::compressInit(VisualNode& root, int idx, int absX) {
const int kids = root.getNumberOfChildren();
auto& na = node_tree.getNA();
bool hasSolved = false;
int leafCnt = 0, expectSolvedCnt = 0, actualSolvedCnt = 0;
statistic[idx].ns = root.getStatus();
statistic[idx].absX = absX;
for (int i = 0; i < kids; i++) {
int kidIdx = root.getChild(i);
VisualNode& kid = *na[kidIdx];
if (kid.hasSolvedChildren()) expectSolvedCnt++;
if (statistic[kidIdx].height >= compressLevel) {
bool kidRes = compressInit(kid, kidIdx, absX + leafCnt);
hasSolved |= kidRes;
leafCnt += statistic[kidIdx].leafCnt;
if (kidRes) actualSolvedCnt++;
}
}
statistic[idx].leafCnt = leafCnt? leafCnt: 1;
if (kids && statistic[idx].height == compressLevel)
statistic[idx].ns = root.hasSolvedChildren()? SOLVED: FAILED;
else if (expectSolvedCnt > actualSolvedCnt)
statistic[idx].ns = SOLVED;
return hasSolved | (statistic[idx].ns == SOLVED);
}示例2: node
forceinline bool
HideFailedCursor::mayMoveDownwards(void) {
VisualNode* n = node();
return (!onlyDirty || n->isDirty()) &&
NodeCursor<VisualNode>::mayMoveDownwards() &&
(n->hasSolvedChildren() || n->getNoOfOpenChildren(na) > 0) &&
(! n->isHidden());
}