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C++ UserList::findUser方法代码示例

本文整理汇总了C++中UserList::findUser方法的典型用法代码示例。如果您正苦于以下问题:C++ UserList::findUser方法的具体用法?C++ UserList::findUser怎么用?C++ UserList::findUser使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在UserList的用法示例。


在下文中一共展示了UserList::findUser方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。

示例1: main


//.........这里部分代码省略.........
												usermenu();
												break;
											}
											case 3:	// delete a wallpost
											{
												int id;
												cout << "Please enter the post ID number you wish to remove." << endl;
												cin >> id;
												currentUser->removeWallPost(id);
												break;
											}
											case 4: // edit personal information
											{
												currentUser->editInformation();
												cout << endl;
												usermenu();
												break;
											}
											case 5: // display personal information
											{
												currentUser->printInformation();
												cout << endl;
												usermenu();
												break;
											}
											case 6:
											{
												char usernamesearch[256];
												cout << "Please enter a user to search." << endl;
												cin.getline (usernamesearch, 256);
												string newusername;
												newusername = fixString(usernamesearch);

												bool searchUser = UserListDatabase->findUser(usernamesearch, currentUser);
												if (searchUser == true){
													cout << "User(s) exists." << endl;
												}
												else{
													cout << "User(s) does not exist." << endl;
												}
												cout << endl;
												usermenu();
												break;
											}
											case 7:
											{
												string friendname;
												cout << "Please enter the name of the user you'd like to add as a friend." << endl;
												cin >> friendname;
												User* friendUser = UserListDatabase->checkUser(friendname);
												bool checkUser = UserListDatabase->validUser(friendname);
												if (checkUser == true){
													if (friendUser->getusername() == currentUser->getusername()){
														cout << "You cannot add yourself as a friend! Loner." << endl;
													}
													else{
														currentUser->addFriend(friendUser);
														friendUser->addPendingFriend(currentUser);
														cout << "Success: Friend request added." << endl;
													}
												}
												else {
													cout << "No user exists." << endl;
												}
												break;
											}
开发者ID:twistedmove,项目名称:CSCI104,代码行数:67,代码来源:social.cpp


注:本文中的UserList::findUser方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。