本文整理汇总了C++中Unicode::reserve方法的典型用法代码示例。如果您正苦于以下问题：C++ Unicode::reserve方法的具体用法？C++ Unicode::reserve怎么用？C++ Unicode::reserve使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Unicode的用法示例。
在下文中一共展示了Unicode::reserve方法的4个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: cut
virtual bool cut(const string& str, vector<vector<string> >& vres) const {
vres.clear();
Unicode unicode;
unicode.reserve(str.size());
TransCode::decode(str, unicode);
Unicode::const_iterator left = unicode.begin();
Unicode::const_iterator right;
for(right = unicode.begin(); right != unicode.end(); right++) {
if(isIn(specialSymbols_, *right)) {
if(left != right) {
cut(left, right, vres);
}
for (vector<vector<string> >::iterator itr = vres.begin(); itr != vres.end(); ++itr) {
itr->resize(itr->size() + 1);
TransCode::encode(right, right + 1, itr->back());
}
left = right + 1;
}
}
if(left != right) {
cut(left, right, vres);
}
return true;
}示例2: cut
virtual bool cut(Unicode::const_iterator begin, Unicode::const_iterator end, vector<Unicode>& res) const
{
vector<Unicode> words;
words.reserve(end - begin);
if(!_mpSeg.cut(begin, end, words))
{
Rcout<<"mpSeg cutDAG failed."<<std::endl;
return false;
}
vector<Unicode> hmmRes;
hmmRes.reserve(end - begin);
Unicode piece;
piece.reserve(end - begin);
for (size_t i = 0, j = 0; i < words.size(); i++)
{
//if mp get a word, it's ok, put it into result
if (1 != words[i].size() || (words[i].size() == 1 && _mpSeg.isUserDictSingleChineseWord(words[i][0])))
{
res.push_back(words[i]);
continue;
}
// if mp get a single one and it is not in userdict, collect it in sequence
j = i;
while (j < words.size() && 1 == words[j].size() && !_mpSeg.isUserDictSingleChineseWord(words[j][0]))
{
piece.push_back(words[j][0]);
j++;
}
// cut the sequence with hmm
if (!_hmmSeg.cut(piece.begin(), piece.end(), hmmRes))
{
Rcout<<"_hmmSeg cut failed."<<std::endl;
return false;
}
//put hmm result to result
for (size_t k = 0; k < hmmRes.size(); k++)
{
res.push_back(hmmRes[k]);
}
//clear tmp vars
piece.clear();
hmmRes.clear();
//let i jump over this piece
i = j - 1;
}
return true;
}示例3: DecodeRunesInString
inline bool DecodeRunesInString(const char* s, size_t len, Unicode& unicode) {
unicode.clear();
RuneStrArray runes;
if (!DecodeRunesInString(s, len, runes)) {
return false;
}
unicode.reserve(runes.size());
for (size_t i = 0; i < runes.size(); i++) {
unicode.push_back(runes[i].rune);
}
return true;
}示例4: Decode
// compiler is expected to optimized this function to avoid return value copy
inline Unicode Decode(const string& str) {
Unicode unicode;
unicode.reserve(str.size());
Decode(str, unicode);
return unicode;
}