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C++ TicTacToe::displayBoard方法代码示例

本文整理汇总了C++中TicTacToe::displayBoard方法的典型用法代码示例。如果您正苦于以下问题:C++ TicTacToe::displayBoard方法的具体用法?C++ TicTacToe::displayBoard怎么用?C++ TicTacToe::displayBoard使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在TicTacToe的用法示例。


在下文中一共展示了TicTacToe::displayBoard方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。

示例1: main

int main(int argc, char const* argv[])
{
    using namespace std;
    char answer;
    cout << "Player 1 [circle] begins, should it be human (enter h) or computer (enter c): ";
    cin >> answer;
    while (!(answer == 'h' || answer == 'c')){
        cout << "Wrong answer, try again: ";
        cin >> answer;
    }
    Player p1(Player1, (answer == 'c' ? true : false));
    cout << "Player 2 [cross], should it be human (enter h) or computer (enter c): ";
    cin >> answer;
    while (!(answer == 'h' || answer == 'c')){
        cout << "Wrong answer, try again: ";
        cin >> answer;
    }
    Player p2(Player2, (answer == 'c' ? true : false));

    TicTacToe game;
    while (!game.getStatus()){ // until nobody won and there are still empty fields 
        game.displayBoard();
        p1.move(game);
        if (game.getStatus() != None) // if sb. won or there is a draw
            break;
        game.displayBoard();
        p2.move(game);
        if (game.getStatus() != None) // if sb. won or there is a draw
            break;
    }
    game.displayBoard();
    switch (game.getStatus()) {
        case Player1:
            cout << "Player 1 won!\n";
            break;
        case Player2:
            cout << "Player 2 won!\n";
            break;
        default:
            cout << "Draw!\n";
            break;

    }
    return 0;
}
开发者ID:palkakrzysiek,项目名称:IT-class,代码行数:45,代码来源:main.cpp


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