本文整理汇总了C++中SyntaxTree::GetNumWords方法的典型用法代码示例。如果您正苦于以下问题：C++ SyntaxTree::GetNumWords方法的具体用法？C++ SyntaxTree::GetNumWords怎么用？C++ SyntaxTree::GetNumWords使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类SyntaxTree的用法示例。
在下文中一共展示了SyntaxTree::GetNumWords方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: SAMT
void SAMT( SyntaxTree &tree, ParentNodes &parents )
{
int numWords = tree.GetNumWords();
SyntaxTree newTree; // to store new nodes
// look through parents to combine children
for(ParentNodes::const_iterator p = parents.begin(); p != parents.end(); p++)
{
const SplitPoints &point = *p;
// neighboring childen: DET+ADJ
if (point.size() >= 3) {
// cerr << "complex parent: ";
// for(int i=0;i<point.size();i++) cerr << point[i] << " ";
// cerr << endl;
for(int i = 0; i+2 < point.size(); i++)
{
// cerr << "\tadding " << point[i] << ";" << point[i+1] << ";" << (point[i+2]-1) << ": " << tree.GetNodes(point[i ],point[i+1]-1)[0]->GetLabel() << "+" << tree.GetNodes(point[i+1],point[i+2]-1)[0]->GetLabel() << endl;
newTree.AddNode( point[i],point[i+2]-1,
tree.GetNodes(point[i ],point[i+1]-1)[0]->GetLabel()
+ "+" +
tree.GetNodes(point[i+1],point[i+2]-1)[0]->GetLabel() );
}
}
if (point.size() >= 4) {
int ps = point.size();
string topLabel = tree.GetNodes(point[0],point[ps-1]-1)[0]->GetLabel();
// cerr << "\tadding " << topLabel + "\\" + tree.GetNodes(point[0],point[1]-1)[0]->GetLabel() << endl;
newTree.AddNode( point[1],point[ps-1]-1,
topLabel
+ "\\" +
tree.GetNodes(point[0],point[1]-1)[0]->GetLabel() );
// cerr << "\tadding " << topLabel + "/" + tree.GetNodes(point[ps-2],point[ps-1]-1)[0]->GetLabel() << endl;
newTree.AddNode( point[0],point[ps-2]-1,
topLabel
+ "/" +
tree.GetNodes(point[ps-2],point[ps-1]-1)[0]->GetLabel() );
}
}
// rules for any bordering constituents...
for(int size = 2; size < numWords; size++)
{
for(int start = 0; start < numWords-size+1; start++)
{
int end = start+size-1;
bool done = false;
if (tree.HasNode( start,end ) || newTree.HasNode( start,end )
|| SAMTLevel <= 1)
{
continue;
}
// if matching two adjacent parse constituents: use ++
for(int mid=start+1; mid<=end && !done; mid++)
{
if (tree.HasNode(start,mid-1) && tree.HasNode(mid,end)) {
// cerr << "\tadding " << tree.GetNodes(start,mid-1)[0]->GetLabel() << "++" << tree.GetNodes(mid, end )[0]->GetLabel() << endl;
newTree.AddNode( start, end,
tree.GetNodes(start,mid-1)[0]->GetLabel()
+ "++" +
tree.GetNodes(mid, end )[0]->GetLabel() );
done = true;
}
}
if (done) continue;
// if matching a constituent A right-minus const. B: use A//B
for(int postEnd=end+1; postEnd<numWords && !done; postEnd++)
{
if (tree.HasNode(start,postEnd) && tree.HasNode(end+1,postEnd))
{
newTree.AddNode( start, end,
tree.GetNodes(start,postEnd)[0]->GetLabel()
+ "//" +
tree.GetNodes(end+1,postEnd)[0]->GetLabel() );
done = true;
}
}
if (done) continue;
// if matching a constituent A left-minus constituent B: use A\\B
for(int preStart=start-1; preStart>=0; preStart--)
{
if (tree.HasNode(preStart,end) && tree.HasNode(preStart,start-1))
{
// cerr << "\tadding " << tree.GetNodes(preStart,end )[0]->GetLabel() << "\\\\" <<tree.GetNodes(preStart,start-1)[0]->GetLabel() << endl;
newTree.AddNode( start, end,
tree.GetNodes(preStart,end )[0]->GetLabel()
+ "\\\\" +
tree.GetNodes(preStart,start-1)[0]->GetLabel() );
done = true;
//.........这里部分代码省略.........