本文整理汇总了C++中StarLink::getTime方法的典型用法代码示例。如果您正苦于以下问题：C++ StarLink::getTime方法的具体用法？C++ StarLink::getTime怎么用？C++ StarLink::getTime使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类StarLink的用法示例。
在下文中一共展示了StarLink::getTime方法的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: calculate
FPType NonAdditivePC::calculate(Path *path, int odIndex) const{
assert(path != NULL && odIndex >=0);
TollType totalToll = 0;
FPType totalTime = 0.0;
for (StarLinkIterator it = path->begin(); it != path->end(); ++it) {
StarLink* link = *it;
totalTime += link->getTime();
totalToll += tolls_[link->getIndex()];
}
return calculate(totalTime, totalToll, odIndex);
};示例2: printMaxShPath
void DAGraph::printMaxShPath(int node){
StarLink *prevMax = (nodes_[node])->maxLink;
int prevNode = -1;
std::cout << "Cost = " << (nodes_[node])->maxDist << std::endl;
FPType cost = 0.0;
while (prevMax != NULL){
prevNode = prevMax->getNodeFromIndex();
cost += prevMax->getFlow() * prevMax->getTime();
std::cout << "[" << prevMax->getNodeToIndex() << ", " << prevNode << "] "
<< prevMax->getFlow() << " - ";
prevMax = (nodes_[prevNode])->maxLink;
}
std::cout << std::endl;
}; 示例3: buildMinMaxTrees
void DAGraph::buildMinMaxTrees(int destIndex){
int index = -1;
for (int i = 0; i < nodeSize_; ++i) {
index = nodeIndexes_[i];
nodes_[index]->minDist = std::numeric_limits<FPType>::infinity( );
nodes_[index]->maxDist = 0.0;
}
nodes_[originIndex_]->minDist = 0.0; // set to zero for origin
// find shortest and longest paths with positive flow
FPType dist = 0.0;
FPType time = 0.0;
int i = beginAscPass();
assert(originIndex_ == i); //-- TODO: theoretically there might be
// an alternative top order that starts with another node --
// not clear what to do in this case
StarLink* link = NULL;
for (; i != -1; i = getNextAscPass()) {
std::list<StarLink*> &linksList = nodes_[i]->incomeLinks;
for (std::list<StarLink*>::iterator it = linksList.begin(); it != linksList.end(); ++it) {
link = *it;
index = link->getNodeFromIndex();
assert(nodes_[index] != NULL);
time = link->getTime();
dist = nodes_[index]->minDist + time; // min dist
if (dist < nodes_[i]->minDist) {
nodes_[i]->minDist = dist;
nodes_[i]->minLink = link;
}
dist = nodes_[index]->maxDist + time; // max dist
if (dist >= nodes_[i]->maxDist) {
nodes_[i]->maxDist = dist;
nodes_[i]->maxLink = link;
}
}
if (i == destIndex) break;
}
};