本文整理汇总了C++中Solution::anagrams方法的典型用法代码示例。如果您正苦于以下问题:C++ Solution::anagrams方法的具体用法?C++ Solution::anagrams怎么用?C++ Solution::anagrams使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Solution
的用法示例。
在下文中一共展示了Solution::anagrams方法的15个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: main
int main(){
vector<string> input = { "lint", "intl", "inlt", "code", };
vector<string> in2 = { "tea", "", "eat", "", "tea", "" };
Solution t;
auto ret = t.anagrams(input);
auto ret2 = t.anagrams(in2);
return 0;
}
示例2: main
int main(){
Solution so;
string s[] = { "c", "c" };
vector<string> v(s,s+2);
so.anagrams(v);
cout << so.myPow(0.00001, -214748364);
return 0;
}
示例3: main
int main(){
Solution so;
string line;
while(getline(cin,line)){
vector<string> words=string2vector<string>(line);
cout<<vector2string<string>(so.anagrams(words)," ")<<endl;
}
}
示例4: main
int main(int argc, char *argv[])
{
Solution sol;
vector<string> vs{"and", "dan"};
vector<string> v = sol.anagrams(vs);
for (auto s : v)
cout << s << endl;
return 0;
}
示例5: main
int main()
{
string s[] = {"ate", "and", "dna", "tea", "eat", "endl", "hello", "ehllo"};
vector<string> str(s, s + 8);
Solution test;
vector<string> ret = test.anagrams(str);
for(int i = 0; i < ret.size(); i++)
cout << ret[i] << endl;
return 0;
}
示例6: main
int main(){
Solution sol;
string a[] = {"foo", "oof", "bar", "arb", "far", "fds", "ofo"};
vector<string> strs(a, a + sizeof(a) / sizeof(string));
vector<string> result = sol.anagrams(strs);
for(int i = 0 ; i < result.size(); ++ i){
cout << result[i] << endl;
}
return 0;
}
示例7: main
int main()
{
Solution s;
vector<string> ins{"", ""};
auto res = s.anagrams(ins);
for (auto & s : res) {
cout << s << endl;
}
return 0;
}
示例8: main
int main() {
Solution sol;
vector<string> strs = {"dog","cat","god","tac"};
vector<string> anagrams = sol.anagrams(strs);
copy(anagrams.begin(), anagrams.end(),
ostream_iterator<decltype(anagrams)::value_type>(cout, " "));
cout << '\n';
return 0;
}
示例9: main
int main()
{
vector<string> strs = {"tea","and","ate","eat","dan"};
Solution s;
vector<string> res;
res = s.anagrams(strs);
for(auto iter = res.begin(); iter != res.end(); iter++) {
cout<<*iter<<" ";
}
return 0;
}
示例10: main
int main(int argc, char * argv[]) {
vector<string> inputs;
inputs.push_back("ape");
inputs.push_back("and");
inputs.push_back("eap");
// inputs.push_back("cat");
Solution solve;
vector<string> output = solve.anagrams(inputs);
UIO<string>::pr(output);
return 0;
}
示例11: main
int main() {
const char *A[] = {
"tea","and","ate","eat","den"
};
vector<string> strs(A, A + 6);
Solution solu = Solution();
vector<string> res = solu.anagrams(strs);
for (vector<string>::iterator it = res.begin(); it != res.end(); it++) {
cout << *it << ", ";
}
cout << endl;
}
示例12: main
int main() {
vector<string> strs {"tea","and","ate","eat","den"};
cout << "Input: " << endl;
for(auto word : strs)
cout << word << " ";
cout << endl;
Solution sol;
vector<string> result = sol.anagrams(strs);
cout << "Output: " << endl;
for(auto word : result)
cout << word << " ";
cout << endl;
}
示例13: main
int main(void){
Solution answer;
string str[] = { "abc", "acb", "acf" };
vector<string> strs;
for (size_t i = 0; i < 3; ++i)
strs.push_back(str[i]);
vector<string> ret = answer.anagrams(strs);
for (size_t i = 0; i < ret.size(); ++i)
cout << ret[i] << " ";
cout << endl;
system("Pause");
return 0;
}
示例14: main
void main(int argc, char *argv[]){
vector<string> strs = { "last", "salt", "diary", "reap", "cook", "dairy", "apple", "pear", "stal", "pea", "ape", "meat" };
cout << "The original words are: ";
for (string ss : strs)
cout << "'" << ss << "' ";
cout << endl;
Solution s;
vector<string> anagramWords = s.anagrams(strs);
cout << "The anagrams words are: ";
for (string ss : anagramWords)
cout << "'" << ss << "' ";
cout << endl;
system("pause");
}
示例15: main
int main()
{
vector<string> temp;
temp.push_back("tea");
temp.push_back("and");
temp.push_back("ate");
temp.push_back("eat");
temp.push_back("den");
Solution s;
vector<string> res=s.anagrams(temp);
for(int i=0;i<res.size();i++)
cout<<res[i]<<endl;
return 0;
}