本文整理汇总了C++中SharedMemBufferPtr::Zero方法的典型用法代码示例。如果您正苦于以下问题：C++ SharedMemBufferPtr::Zero方法的具体用法？C++ SharedMemBufferPtr::Zero怎么用？C++ SharedMemBufferPtr::Zero使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类SharedMemBufferPtr的用法示例。
在下文中一共展示了SharedMemBufferPtr::Zero方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: exception
uint16_t
CQ::Reap(uint16_t &ceRemain, SharedMemBufferPtr memBuffer, uint32_t &isrCount,
uint16_t ceDesire, bool zeroMem)
{
int rc;
struct nvme_reap reap;
// The tough part of reaping all which can be reaped, indicated by
// (ceDesire == 0), is that CE's can be arriving from hdw between the time
// one calls ReapInquiry() and Reap(). In essence this indicates we really
// can never know for certain how many there are to be reaped, and thus
// never really knowing how large to make a buffer to reap CE's into.
// The solution is to enforce brute force methods by allocating max CE's
if (ceDesire == 0) {
// Per NVME spec: 1 empty CE implies a full CQ, can't truly fill all
ceDesire = (GetNumEntries() - 1);
} else if (ceDesire > (GetNumEntries() - 1)) {
// Per NVME spec: 1 empty CE implies a full CQ, can't truly fill all
LOG_NRM("Requested num of CE's exceeds max can fit, resizing");
ceDesire = (GetNumEntries() - 1);
}
// Allocate enough space to contain the CE's
memBuffer->Init(GetEntrySize()*ceDesire);
if (zeroMem)
memBuffer->Zero();
reap.q_id = GetQId();
reap.elements = ceDesire;
reap.size = memBuffer->GetBufSize();
reap.buffer = memBuffer->GetBuffer();
if ((rc = ioctl(mFd, NVME_IOCTL_REAP, &reap)) < 0) {
LOG_ERR("Error during reaping CE's, rc =%d", rc);
throw exception();
}
isrCount = reap.isr_count;
ceRemain = reap.num_remaining;
LOG_NRM("Reaped %d CE's, %d remain, from CQ %d, ISR count: %d",
reap.num_reaped, reap.num_remaining, GetQId(), isrCount);
return reap.num_reaped;
}