本文整理汇总了C++中Search::hasSolution方法的典型用法代码示例。如果您正苦于以下问题：C++ Search::hasSolution方法的具体用法？C++ Search::hasSolution怎么用？C++ Search::hasSolution使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Search的用法示例。
在下文中一共展示了Search::hasSolution方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: main
int main( int argc, char ** argv ) {
std::string *filename = NULL;
int times = 0, cost = 0, innerTimes = 0;
bool mazeValid = false;
FileHandler *file = NULL;
Maze *maze = new Maze( ROWS, COLS );
GeneticAlgorithm *algorithm = new GeneticAlgorithm( maze );
Search *search = new Search( maze );
Agent *agent = new Agent( maze );
if( argc == 2 ) {
filename = new std::string( argv[1] );
} else {
filename = new std::string( "maze.txt" );
}
algorithm->setMinIterations( MIN_ITERATIONS );
algorithm->setMutationRate( MUTATION_RATE );
algorithm->setCrossOverRate( CROSS_OVER_RATE );
maze->setRandomRate( RANDOM_RATE );
maze->generateFirstPopulation();
do {
times++;
algorithm->run();
mazeValid = maze->searchDoors();
// Se ele nao tem portas suficientes para testar
// Executa o A.G denovo
if( ! mazeValid ) {
continue;
}
while( ( mazeValid = maze->selectDoors( MIN_COST, MAX_COST ) ) ) {
// Se a menor distancia entre a entrada e saida for maior
// que o MAX_COST, entao nao ha caminho valido
if( ! maze->validDistance( MIN_COST, MAX_COST ) ) {
continue;
}
cost = search->hasSolution( true ); // Usa o algoritmo A*, mais rapido a convergencia...
if( cost >= MIN_COST && cost <= MAX_COST ) {
break;
}
innerTimes++;
}
if( times % 10 == 0 ) {
std::cout << times << ": " << DataNode::ctor << ", " << DataNode::dtor << std::endl;
}
} while( ! mazeValid );
agent->run();
try {
file = new FileHandler( filename->c_str() );
file->printMaze( maze );
std::cout << "Maze dump in " << *filename << std::endl;
} catch( int e ) {
std::cout << file->getErrorMessage();
}
delete agent;
delete search;
delete maze;
delete filename;
delete algorithm;
delete file;
return 0;
}