本文整理汇总了C++中QuickSums::minSums方法的典型用法代码示例。如果您正苦于以下问题:C++ QuickSums::minSums方法的具体用法?C++ QuickSums::minSums怎么用?C++ QuickSums::minSums使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类QuickSums
的用法示例。
在下文中一共展示了QuickSums::minSums方法的3个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: TEST
void TEST(string numbers, int sum, int expected)
{
clock_t start, end;
double cpu_time_used;
start = clock();
QuickSums quickSums;
int result = quickSums.minSums( numbers, sum);
assert( result == expected );
end = clock();
cpu_time_used = ((double) (end - start));
cout<<"Time taken : "<<cpu_time_used<<endl;
}
示例2: test3
int test3() {
string numbers = "99999";
int sum = 100;
QuickSums* pObj = new QuickSums();
clock_t start = clock();
int result = pObj->minSums(numbers, sum);
clock_t end = clock();
delete pObj;
int expected = -1;
if(result == expected) {
cout << "Test Case 3: Passed! Time: " << static_cast<double>(end-start)/CLOCKS_PER_SEC << " seconds" << endl;
return 0;
} else {
cout << "Test Case 3: Failed! Time: " << static_cast<double>(end-start)/CLOCKS_PER_SEC << " seconds" << endl;
return 1;
}
}
示例3: test1
double test1() {
string p0 = "1110";
int p1 = 3;
QuickSums * obj = new QuickSums();
clock_t start = clock();
int my_answer = obj->minSums(p0, p1);
clock_t end = clock();
delete obj;
cout <<"Time: " <<(double)(end-start)/CLOCKS_PER_SEC <<" seconds" <<endl;
int p2 = 3;
cout <<"Desired answer: " <<endl;
cout <<"\t" << p2 <<endl;
cout <<"Your answer: " <<endl;
cout <<"\t" << my_answer <<endl;
if (p2 != my_answer) {
cout <<"DOESN'T MATCH!!!!" <<endl <<endl;
return -1;
}
else {
cout <<"Match :-)" <<endl <<endl;
return (double)(end-start)/CLOCKS_PER_SEC;
}
}