本文整理汇总了C++中QuadTreeNode::getActualLodLevel方法的典型用法代码示例。如果您正苦于以下问题：C++ QuadTreeNode::getActualLodLevel方法的具体用法？C++ QuadTreeNode::getActualLodLevel怎么用？C++ QuadTreeNode::getActualLodLevel使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类QuadTreeNode的用法示例。
在下文中一共展示了QuadTreeNode::getActualLodLevel方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: updateIndexBuffers
void QuadTreeNode::updateIndexBuffers()
{
if (hasChunk())
{
// Fetch a suitable index buffer (which may be shared)
size_t ourLod = getActualLodLevel();
int flags = 0;
for (int i=0; i<4; ++i)
{
QuadTreeNode* neighbour = getNeighbour((Direction)i);
// If the neighbour isn't currently rendering itself,
// go up until we find one. NOTE: We don't need to go down,
// because in that case neighbour's detail would be higher than
// our detail and the neighbour would handle stitching by itself.
while (neighbour && !neighbour->hasChunk())
neighbour = neighbour->getParent();
size_t lod = 0;
if (neighbour)
lod = neighbour->getActualLodLevel();
if (lod <= ourLod) // We only need to worry about neighbours less detailed than we are -
lod = 0; // neighbours with more detail will do the stitching themselves
// Use 4 bits for each LOD delta
if (lod > 0)
{
assert (lod - ourLod < (1 << 4));
flags |= int(lod - ourLod) << (4*i);
}
}
flags |= 0 /*((int)mAdditionalLod)*/ << (4*4);
mChunk->setIndexBuffer(mTerrain->getBufferCache().getIndexBuffer(flags));
}
else if (hasChildren())
{
for (int i=0; i<4; ++i)
mChildren[i]->updateIndexBuffers();
}
}