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C++ QSMember::owner方法代码示例

本文整理汇总了C++中QSMember::owner方法的典型用法代码示例。如果您正苦于以下问题:C++ QSMember::owner方法的具体用法?C++ QSMember::owner怎么用?C++ QSMember::owner使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在QSMember的用法示例。


在下文中一共展示了QSMember::owner方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。

示例1: objectType

/*!
  Tries to resolve a member named \a name. If it is found \a mem is
  initialized with the result and the class defining this member is
  returned. In case of a failed search, 0 is returned and the content
  of \a mem is undefined.
*/
const QSClass *QSObject::resolveMember(const QString &name,
                                       QSMember *mem,
                                       const QSClass *owner,
                                       int *offset) const
{
  Q_ASSERT(offset);
  Q_ASSERT(mem);
  Q_ASSERT(!name.isEmpty());
  if (!owner)
    owner = objectType();
  QPtrList<QSClass> enclosing;
  QSMember stackedMember;
  while (owner) {
    if (owner->member(*offset == 0 ? this : 0, name, mem)) {
      return owner;
    } else if (mem->type() == QSMember::Identifier && !stackedMember.isDefined()) {
      stackedMember = *mem;
    }
    if (owner->enclosingClass())
      enclosing.append(owner->enclosingClass());
    owner = owner->base();
  }

  const QSClass *eClass = enclosing.first();
  while (eClass) {
    const QSClass *enc =
      resolveMember(name, mem, eClass, &(++(*offset)));
    if (enc) {
      if (mem->type() == QSMember::Identifier)
        if (!stackedMember.isDefined())
          stackedMember = *mem;
        else
          return enc;
    } else {
      --(*offset);
    }
    eClass = enclosing.next();
  }

  if (stackedMember.isDefined()) {
    *mem = stackedMember;
    return stackedMember.owner();

  }

  return 0;
}
开发者ID:miguelet17,项目名称:eneboo,代码行数:53,代码来源:qsobject.cpp


注:本文中的QSMember::owner方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。