本文整理汇总了C++中PointErasingTwo::getMaximum方法的典型用法代码示例。如果您正苦于以下问题：C++ PointErasingTwo::getMaximum方法的具体用法？C++ PointErasingTwo::getMaximum怎么用？C++ PointErasingTwo::getMaximum使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类PointErasingTwo的用法示例。
在下文中一共展示了PointErasingTwo::getMaximum方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: main
int main()
{
PointErasingTwo a;
int myints[] = { 1, 2, 1, 1, 0, 4, 3 };
vector<int> y (myints, myints + sizeof(myints) / sizeof(int) );
cout<<a.getMaximum(y);
return 0;
}示例2: KawigiEdit_RunTest
// BEGIN KAWIGIEDIT TESTING
// Generated by KawigiEdit 2.1.4 (beta) modified by pivanof
bool KawigiEdit_RunTest(int testNum, vector <int> p0, bool hasAnswer, int p1) {
cout << "Test " << testNum << ": [" << "{";
for (int i = 0; int(p0.size()) > i; ++i) {
if (i > 0) {
cout << ",";
}
cout << p0[i];
}
cout << "}";
cout << "]" << endl;
PointErasingTwo *obj;
int answer;
obj = new PointErasingTwo();
clock_t startTime = clock();
answer = obj->getMaximum(p0);
clock_t endTime = clock();
delete obj;
bool res;
res = true;
cout << "Time: " << double(endTime - startTime) / CLOCKS_PER_SEC << " seconds" << endl;
if (hasAnswer) {
cout << "Desired answer:" << endl;
cout << "\t" << p1 << endl;
}
cout << "Your answer:" << endl;
cout << "\t" << answer << endl;
if (hasAnswer) {
res = answer == p1;
}
if (!res) {
cout << "DOESN'T MATCH!!!!" << endl;
} else if (double(endTime - startTime) / CLOCKS_PER_SEC >= 2) {
cout << "FAIL the timeout" << endl;
res = false;
} else if (hasAnswer) {
cout << "Match :-)" << endl;
} else {
cout << "OK, but is it right?" << endl;
}
cout << "" << endl;
return res;
}