本文整理汇总了C++中PhpFunc::isMethod方法的典型用法代码示例。如果您正苦于以下问题：C++ PhpFunc::isMethod方法的具体用法？C++ PhpFunc::isMethod怎么用？C++ PhpFunc::isMethod使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类PhpFunc的用法示例。
在下文中一共展示了PhpFunc::isMethod方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: writeFunction
static void writeFunction(std::ostream& out, const PhpFunc& func) {
auto flags = (func.flags() & FUNC_FLAG_MASK) | IsSystem | IsNothing;
if (flags & RefVariableArguments) {
flags |= VariableArguments;
}
if (flags & MixedVariableArguments) {
flags |= RefVariableArguments | VariableArguments;
}
if (!func.isMethod() || !(flags & VISIBILITY_MASK)) {
flags |= IsPublic;
}
if (func.isReturnRef()) {
flags |= IsReference;
}
out << " " << castLong(flags, true)
<< ", \"" << escapeCpp(func.getPhpName()) << "\", " << "\"\", "
<< castLong(0) << ", "
<< castLong(0) << ",\n";
out << " \""
<< escapeCpp(genDocComment(func, func.className()))
<< "\",\n";
DataType rko = func.returnKindOf();
if (rko == KindOfAny) {
// ClassInfo::MethodInfo expects this for Any/Variant
// TODO: Fix that broken assumption
rko = KindOfInvalid;
}
out << " " << castLong(rko, true) << ",\n";
for (auto &p : func.params()) {
long attr = IsNothing;
DataType ko = p.kindOf();
if (p.isRef()) {
// We don't declare param type as KindOfRef
// as then the caller will try to cast it as such
attr |= IsReference;
ko = KindOfAny;
}
if (ko == KindOfAny) {
// TODO: See above
ko = KindOfInvalid;
}
out << " "
<< castLong(attr, true) << ", "
<< "\"" << escapeCpp(p.name()) << "\", \"\", "
<< castLong(ko, true) << ",\n";
auto ser = p.getDefaultSerialized();
auto val = p.getDefaultPhp();
out << " "
<< "\"" << escapeCpp(ser) << "\", " << castLong(ser.size()) << ", "
<< "\"" << escapeCpp(val) << "\", " << castLong(val.size()) << ", "
<< "NULL,\n";
}
out << " NULL,\n"
<< " NULL,\n"
<< " NULL,\n";
}