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C++ OctreeElementPointer::isParentOf方法代码示例

本文整理汇总了C++中OctreeElementPointer::isParentOf方法的典型用法代码示例。如果您正苦于以下问题:C++ OctreeElementPointer::isParentOf方法的具体用法?C++ OctreeElementPointer::isParentOf怎么用?C++ OctreeElementPointer::isParentOf使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在OctreeElementPointer的用法示例。


在下文中一共展示了OctreeElementPointer::isParentOf方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。

示例1: postRecursion

bool UpdateEntityOperator::postRecursion(OctreeElementPointer element) {
    // Post-recursion is the unwinding process. For this operation, while we
    // unwind we want to mark the path as being dirty if we changed it below.
    // We might have two paths, one for the old entity and one for the new entity.
    bool keepSearching = !_foundOld || !_foundNew;

    bool subtreeContainsOld = subTreeContainsOldEntity(element);
    bool subtreeContainsNew = subTreeContainsNewEntity(element);

    // As we unwind, if we're in either of these two paths, we mark our element
    // as dirty.
    if ((_foundOld && subtreeContainsOld) ||
            (_foundNew && subtreeContainsNew)) {
        element->markWithChangedTime();
    }

    // It's not OK to prune if we have the potential of deleting the original containig element.
    // because if we prune the containing element then new might end up reallocating the same memory later 
    // and that will confuse our logic.
    // 
    // it's ok to prune if:
    // 1) we're not removing the old
    // 2) we are removing the old, but this subtree doesn't contain the old
    // 3) we are removing the old, this subtree contains the old, but this element isn't a direct parent of _containingElement
    if (!_removeOld || !subtreeContainsOld || !element->isParentOf(_containingElement)) {
        EntityTreeElementPointer entityTreeElement = std::static_pointer_cast<EntityTreeElement>(element);
        entityTreeElement->pruneChildren(); // take this opportunity to prune any empty leaves
    }
    
    return keepSearching; // if we haven't yet found it, keep looking
}
开发者ID:GabrielPathfinder,项目名称:hifi,代码行数:31,代码来源:UpdateEntityOperator.cpp


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