本文整理汇总了C++中MessageFormat::getArgTypeCount方法的典型用法代码示例。如果您正苦于以下问题：C++ MessageFormat::getArgTypeCount方法的具体用法？C++ MessageFormat::getArgTypeCount怎么用？C++ MessageFormat::getArgTypeCount使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类MessageFormat的用法示例。
在下文中一共展示了MessageFormat::getArgTypeCount方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: resultNumber
void
TimeUnitFormat::parseObject(const UnicodeString& source,
Formattable& result,
ParsePosition& pos) const {
Formattable resultNumber(0.0);
UBool withNumberFormat = false;
TimeUnit::UTimeUnitFields resultTimeUnit = TimeUnit::UTIMEUNIT_FIELD_COUNT;
int32_t oldPos = pos.getIndex();
int32_t newPos = -1;
int32_t longestParseDistance = 0;
UnicodeString* countOfLongestMatch = NULL;
#ifdef TMUTFMT_DEBUG
char res[1000];
source.extract(0, source.length(), res, "UTF-8");
std::cout << "parse source: " << res << "\n";
#endif
// parse by iterating through all available patterns
// and looking for the longest match.
for (TimeUnit::UTimeUnitFields i = TimeUnit::UTIMEUNIT_YEAR;
i < TimeUnit::UTIMEUNIT_FIELD_COUNT;
i = (TimeUnit::UTimeUnitFields)(i+1)) {
Hashtable* countToPatterns = fTimeUnitToCountToPatterns[i];
int32_t elemPos = UHASH_FIRST;
const UHashElement* elem = NULL;
while ((elem = countToPatterns->nextElement(elemPos)) != NULL){
const UHashTok keyTok = elem->key;
UnicodeString* count = (UnicodeString*)keyTok.pointer;
#ifdef TMUTFMT_DEBUG
count->extract(0, count->length(), res, "UTF-8");
std::cout << "parse plural count: " << res << "\n";
#endif
const UHashTok valueTok = elem->value;
// the value is a pair of MessageFormat*
MessageFormat** patterns = (MessageFormat**)valueTok.pointer;
for (UTimeUnitFormatStyle style = UTMUTFMT_FULL_STYLE; style < UTMUTFMT_FORMAT_STYLE_COUNT;
style = (UTimeUnitFormatStyle)(style + 1)) {
MessageFormat* pattern = patterns[style];
pos.setErrorIndex(-1);
pos.setIndex(oldPos);
// see if we can parse
Formattable parsed;
pattern->parseObject(source, parsed, pos);
if (pos.getErrorIndex() != -1 || pos.getIndex() == oldPos) {
continue;
}
#ifdef TMUTFMT_DEBUG
std::cout << "parsed.getType: " << parsed.getType() << "\n";
#endif
Formattable tmpNumber(0.0);
if (pattern->getArgTypeCount() != 0) {
Formattable& temp = parsed[0];
if (temp.getType() == Formattable::kString) {
UnicodeString tmpString;
UErrorCode pStatus = U_ZERO_ERROR;
getNumberFormat().parse(temp.getString(tmpString), tmpNumber, pStatus);
if (U_FAILURE(pStatus)) {
continue;
}
} else if (temp.isNumeric()) {
tmpNumber = temp;
} else {
continue;
}
}
int32_t parseDistance = pos.getIndex() - oldPos;
if (parseDistance > longestParseDistance) {
if (pattern->getArgTypeCount() != 0) {
resultNumber = tmpNumber;
withNumberFormat = true;
} else {
withNumberFormat = false;
}
resultTimeUnit = i;
newPos = pos.getIndex();
longestParseDistance = parseDistance;
countOfLongestMatch = count;
}
}
}
}
/* After find the longest match, parse the number.
* Result number could be null for the pattern without number pattern.
* such as unit pattern in Arabic.
* When result number is null, use plural rule to set the number.
*/
if (withNumberFormat == false && longestParseDistance != 0) {
// set the number using plurrual count
if (0 == countOfLongestMatch->compare(PLURAL_COUNT_ZERO, 4)) {
resultNumber = Formattable(0.0);
} else if (0 == countOfLongestMatch->compare(PLURAL_COUNT_ONE, 3)) {
resultNumber = Formattable(1.0);
} else if (0 == countOfLongestMatch->compare(PLURAL_COUNT_TWO, 3)) {
resultNumber = Formattable(2.0);
} else {
// should not happen.
// TODO: how to handle?
resultNumber = Formattable(3.0);
}
}
if (longestParseDistance == 0) {
//.........这里部分代码省略.........
示例2: while
void
TimeUnitFormat::parseObject(const UnicodeString& source,
Formattable& result,
ParsePosition& pos) const {
double resultNumber = -1;
UBool withNumberFormat = false;
TimeUnit::UTimeUnitFields resultTimeUnit = TimeUnit::UTIMEUNIT_FIELD_COUNT;
int32_t oldPos = pos.getIndex();
int32_t newPos = -1;
int32_t longestParseDistance = 0;
UnicodeString* countOfLongestMatch = NULL;
#ifdef TMUTFMT_DEBUG
char res[1000];
source.extract(0, source.length(), res, "UTF-8");
std::cout << "parse source: " << res << "\n";
#endif
// parse by iterating through all available patterns
// and looking for the longest match.
for (TimeUnit::UTimeUnitFields i = TimeUnit::UTIMEUNIT_YEAR;
i < TimeUnit::UTIMEUNIT_FIELD_COUNT;
i = (TimeUnit::UTimeUnitFields)(i+1)) {
Hashtable* countToPatterns = fTimeUnitToCountToPatterns[i];
int32_t elemPos = -1;
const UHashElement* elem = NULL;
while ((elem = countToPatterns->nextElement(elemPos)) != NULL){
const UHashTok keyTok = elem->key;
UnicodeString* count = (UnicodeString*)keyTok.pointer;
#ifdef TMUTFMT_DEBUG
count->extract(0, count->length(), res, "UTF-8");
std::cout << "parse plural count: " << res << "\n";
#endif
const UHashTok valueTok = elem->value;
// the value is a pair of MessageFormat*
MessageFormat** patterns = (MessageFormat**)valueTok.pointer;
for (EStyle style = kFull; style < kTotal; style = (EStyle)(style + 1)) {
MessageFormat* pattern = patterns[style];
pos.setErrorIndex(-1);
pos.setIndex(oldPos);
// see if we can parse
Formattable parsed;
pattern->parseObject(source, parsed, pos);
if (pos.getErrorIndex() != -1 || pos.getIndex() == oldPos) {
continue;
}
#ifdef TMUTFMT_DEBUG
std::cout << "parsed.getType: " << parsed.getType() << "\n";
#endif
double tmpNumber = 0;
if (pattern->getArgTypeCount() != 0) {
// pattern with Number as beginning, such as "{0} d".
// check to make sure that the timeUnit is consistent
Formattable& temp = parsed[0];
if (temp.getType() == Formattable::kDouble) {
tmpNumber = temp.getDouble();
} else if (temp.getType() == Formattable::kLong) {
tmpNumber = temp.getLong();
} else {
continue;
}
UnicodeString select = fPluralRules->select(tmpNumber);
#ifdef TMUTFMT_DEBUG
select.extract(0, select.length(), res, "UTF-8");
std::cout << "parse plural select count: " << res << "\n";
#endif
if (*count != select) {
continue;
}
}
int32_t parseDistance = pos.getIndex() - oldPos;
if (parseDistance > longestParseDistance) {
if (pattern->getArgTypeCount() != 0) {
resultNumber = tmpNumber;
withNumberFormat = true;
} else {
withNumberFormat = false;
}
resultTimeUnit = i;
newPos = pos.getIndex();
longestParseDistance = parseDistance;
countOfLongestMatch = count;
}
}
}
}
/* After find the longest match, parse the number.
* Result number could be null for the pattern without number pattern.
* such as unit pattern in Arabic.
* When result number is null, use plural rule to set the number.
*/
if (withNumberFormat == false && longestParseDistance != 0) {
// set the number using plurrual count
if ( *countOfLongestMatch == PLURAL_COUNT_ZERO ) {
resultNumber = 0;
} else if ( *countOfLongestMatch == PLURAL_COUNT_ONE ) {
resultNumber = 1;
} else if ( *countOfLongestMatch == PLURAL_COUNT_TWO ) {
resultNumber = 2;
} else {
// should not happen.
// TODO: how to handle?
//.........这里部分代码省略.........