本文整理汇总了C++中LSLocationList::rend方法的典型用法代码示例。如果您正苦于以下问题：C++ LSLocationList::rend方法的具体用法？C++ LSLocationList::rend怎么用？C++ LSLocationList::rend使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类LSLocationList的用法示例。
在下文中一共展示了LSLocationList::rend方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: reduce
void LSLocation::reduce(LSLocation &Base, SILModule *M, LSLocationSet &Locs,
TypeExpansionAnalysis *TE) {
// First, construct the LSLocation by appending the projection path from the
// accessed node to the leaf nodes.
LSLocationList Nodes;
ProjectionPath &BasePath = Base.getPath().getValue();
for (const auto &P :
TE->getTypeExpansionProjectionPaths(Base.getType(), M, TEKind::TENode)) {
Nodes.push_back(LSLocation(Base.getBase(), P.getValue(), BasePath));
}
// Second, go from leaf nodes to their parents. This guarantees that at the
// point the parent is processed, its children have been processed already.
for (auto I = Nodes.rbegin(), E = Nodes.rend(); I != E; ++I) {
LSLocationList FirstLevel;
I->getFirstLevelLSLocations(FirstLevel, M);
// Reached the end of the projection tree, this is a leaf node.
if (FirstLevel.empty())
continue;
// If this is a class reference type, we have reached end of the type tree.
if (I->getType().getClassOrBoundGenericClass())
continue;
// This is NOT a leaf node, check whether all its first level children are
// alive.
bool Alive = true;
for (auto &X : FirstLevel) {
Alive &= Locs.find(X) != Locs.end();
}
// All first level locations are alive, create the new aggregated location.
if (Alive) {
for (auto &X : FirstLevel)
Locs.erase(X);
Locs.insert(*I);
}
}
}