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C++ IdMap::find方法代码示例

本文整理汇总了C++中IdMap::find方法的典型用法代码示例。如果您正苦于以下问题:C++ IdMap::find方法的具体用法?C++ IdMap::find怎么用?C++ IdMap::find使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在IdMap的用法示例。


在下文中一共展示了IdMap::find方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。

示例1: CalcMetrics

//
// CalcMetrics
// - Loop through the history and pre-calculate metrics used in the training 
// - Also re-number the customer id's to fit in a fixed array
//
void Engine::CalcMetrics()
{
    int i, cid;
    IdItr itr;

    wprintf(L"\nCalculating intermediate metrics\n");

    // Process each row in the training set
    for (i=0; i<m_nRatingCount; i++)
    {
        Data* rating = m_aRatings + i;

        // Increment movie stats
        m_aMovies[rating->MovieId].RatingCount++;
        m_aMovies[rating->MovieId].RatingSum += rating->Rating;
        
        // Add customers (using a map to re-number id's to array indexes) 
        itr = m_mCustIds.find(rating->CustId); 
        if (itr == m_mCustIds.end())
        {
            cid = 1 + (int)m_mCustIds.size();

            // Reserve new id and add lookup
            m_mCustIds[rating->CustId] = cid;

            // Store off old sparse id for later
            m_aCustomers[cid].CustomerId = rating->CustId;

            // Init vars to zero
            m_aCustomers[cid].RatingCount = 0;
            m_aCustomers[cid].RatingSum = 0;
        }
        else
        {
            cid = itr->second;
        }

        // Swap sparse id for compact one
        rating->CustId = cid;

        m_aCustomers[cid].RatingCount++;
        m_aCustomers[cid].RatingSum += rating->Rating;
    }

    // Do a follow-up loop to calc movie averages
    for (i=0; i<MAX_MOVIES; i++)
    {
        Movie* movie = m_aMovies+i;
        movie->RatingAvg = movie->RatingSum / (1.0 * movie->RatingCount);
        movie->PseudoAvg = (3.23 * 25 + movie->RatingSum) / (25.0 + movie->RatingCount);
    }
}
开发者ID:dpipemazo,项目名称:netflix_challenge,代码行数:57,代码来源:sample.cpp


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