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C++ Foo::setBar方法代码示例

本文整理汇总了C++中Foo::setBar方法的典型用法代码示例。如果您正苦于以下问题:C++ Foo::setBar方法的具体用法?C++ Foo::setBar怎么用?C++ Foo::setBar使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在Foo的用法示例。


在下文中一共展示了Foo::setBar方法的3个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。

示例1: KAGUYA_TEST_FUNCTION_DEF

KAGUYA_TEST_FUNCTION_DEF(native_function_call_test)(kaguya::State& state)
{
	using namespace kaguya::nativefunction;
	Foo foo;
	state.newRef(6).push();
	state.newRef(9).push();
	state.newRef(2).push();

	call(state.state(), &free_standing_function);

	lua_settop(state.state(), 0);
	state.newRef(&foo).push();
	state.newRef("Bar").push();
	call(state.state(), &Foo::setBar);
#if KAGUYA_USE_CPP11
	state.newRef(&foo).push();
	state.newRef(9).push();
	call(state.state(), [](Foo* foo, int b) {
		foo->setBar("fromlambda");
	});
	TEST_EQUAL(foo.bar, "fromlambda");

	std::string capture("capture");
	call(state.state(), [=](Foo* foo, int b) {
		foo->setBar(capture + "lambda");
	});
	TEST_EQUAL(foo.bar, "capturelambda");
#endif

	lua_settop(state.state(), 0);
}
开发者ID:lyzardiar,项目名称:kaguya,代码行数:31,代码来源:test_03_function.cpp

示例2: main

int main(int argc, char *argv[])
{
  cout << "main:  This routine tests const conditions." << endl;

  Foo F;
  RCP<Bar> Bptr = rcp(new Bar);
  Bptr->setx(10.0);
  F.setBar(Bptr);
  cout << "Correct output is x = 10." << endl;
  cout << "x = " << Bptr->getx() << endl;

  F.test1(Bptr);
  cout << "Correct output is x = 15." << endl;
  cout << "x = " << Bptr->getx() << endl;

  // This demonstrates that Bptr was overwritten in this member fcn call with a
  // different RCP object, which is only possible because the argument
  // list definition was nonconst.
  F.test3(Bptr);
  cout << "Correct output is x = 25." << endl;
  cout << "x = " << Bptr->getx() << endl;

  Bptr = F.test5();
  cout << "Correct output is x = 15." << endl;
  cout << "x = " << Bptr->getx() << endl;

  Bptr->setx(35.0);
//  Bptr = F.test6(); // not allowed because Bptr is nonconst and output of test6 is const
  RCP<const Bar> BptrConst = rcp(new Bar(40.0));
  F.setConstBar(BptrConst);
  cout << "Correct output is x = 40." << endl;
  cout << "x = " << F.test6()->getx() << endl;  // valid because we put const after Bar::getx

  Bptr = F.test7();
  cout << "Correct output is x = 35." << endl;
  cout << "x = " << Bptr->getx() << endl;  

  Bptr = F.test8();
  cout << "Correct output is x = 45." << endl;
  cout << "x = " << Bptr->getx() << endl;  
  //F.test8() = rcp(new Bar(50.0)); // not allowed because output is const.

  F.test9() = rcp(new Bar(60.0)); // allowed because output is nonconst, but
  // this is crazy.  Especially since the object that is modified is a copied
  // object, so we don't have access to it after this call.

  F.test10() = rcp(new Bar(65.0));  // allowed because output is nonconst, and
  //this does something strange, as it modifies the internal data to the class
  //  through a nonconst reference passed out.
  Bptr = F.test7(); // grab it back out with const output
  cout << "Correct output is x = 65." << endl;
  cout << "x = " << Bptr->getx() << endl;  

//  F.test7() = rcp(new Bar(70.0));  // not allowed because output is const, this
  // is the expected behavior.  You shouldn't be able to do assignments like this.

  BptrConst = F.test12();
  cout << "Correct output is x = 40." << endl;
  cout << "x = " << BptrConst->getx() << endl;  
  //Bptr = F.test12(); // not allowed because Bptr is nonconst

  BptrConst = F.test13(); // this is okay.
  cout << "Correct output is x = 40." << endl;
  cout << "x = " << BptrConst->getx() << endl;  

  Bptr = F.test14(); // this is okay.
  cout << "Correct output is x = 65." << endl;
  cout << "x = " << Bptr->getx() << endl;  

  Bptr = F.test15(); // this is okay.
  cout << "Correct output is x = 65." << endl;
  cout << "x = " << Bptr->getx() << endl;  


  return(0);
}
开发者ID:00liujj,项目名称:trilinos,代码行数:76,代码来源:cxx_main.cpp

示例3: reffun

void reffun(Foo& ref)
{
	ref.setBar("BarBar");
}
开发者ID:lyzardiar,项目名称:kaguya,代码行数:4,代码来源:test_03_function.cpp


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