本文整理汇总了C++中Exp::isRegOf方法的典型用法代码示例。如果您正苦于以下问题:C++ Exp::isRegOf方法的具体用法?C++ Exp::isRegOf怎么用?C++ Exp::isRegOf使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Exp
的用法示例。
在下文中一共展示了Exp::isRegOf方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: substitute
// Substitute s into all members of the set
void LocationSet::substitute(Assign& a)
{
Exp* lhs = a.getLeft();
if (lhs == NULL) return;
Exp* rhs = a.getRight();
if (rhs == NULL) return; // ? Will this ever happen?
std::set<Exp*, lessExpStar>::iterator it;
// Note: it's important not to change the pointer in the set of pointers to expressions, without removing and
// inserting again. Otherwise, the set becomes out of order, and operations such as set comparison fail!
// To avoid any funny behaviour when iterating the loop, we use the following two sets
LocationSet removeSet; // These will be removed after the loop
LocationSet removeAndDelete; // These will be removed then deleted
LocationSet insertSet; // These will be inserted after the loop
bool change;
for (it = lset.begin(); it != lset.end(); it++)
{
Exp* loc = *it;
Exp* replace;
if (loc->search(lhs, replace))
{
if (rhs->isTerminal())
{
// This is no longer a location of interest (e.g. %pc)
removeSet.insert(loc);
continue;
}
loc = loc->clone()->searchReplaceAll(lhs, rhs, change);
if (change)
{
loc = loc->simplifyArith();
loc = loc->simplify();
// If the result is no longer a register or memory (e.g.
// r[28]-4), then delete this expression and insert any
// components it uses (in the example, just r[28])
if (!loc->isRegOf() && !loc->isMemOf())
{
// Note: can't delete the expression yet, because the
// act of insertion into the remove set requires silent
// calls to the compare function
removeAndDelete.insert(*it);
loc->addUsedLocs(insertSet);
continue;
}
// Else we just want to replace it
// Regardless of whether the top level expression pointer has
// changed, remove and insert it from the set of pointers
removeSet.insert(*it); // Note: remove the unmodified ptr
insertSet.insert(loc);
}
}
}
makeDiff(removeSet); // Remove the items to be removed
makeDiff(removeAndDelete); // These are to be removed as well
makeUnion(insertSet); // Insert the items to be added
// Now delete the expressions that are no longer needed
std::set<Exp*, lessExpStar>::iterator dd;
for (dd = removeAndDelete.lset.begin(); dd != removeAndDelete.lset.end();
dd++)
delete *dd; // Plug that memory leak
}
示例2: renameBlockVars
bool DataFlow::renameBlockVars(UserProc* proc, int n, bool clearStacks /* = false */ ) {
if (++progress > 200) {
std::cerr << 'r' << std::flush;
progress = 0;
}
bool changed = false;
// Need to clear the Stacks of old, renamed locations like m[esp-4] (these will be deleted, and will cause compare
// failures in the Stacks, so it can't be correctly ordered and hence balanced etc, and will lead to segfaults)
if (clearStacks) Stacks.clear();
// For each statement S in block n
BasicBlock::rtlit rit; StatementList::iterator sit;
PBB bb = BBs[n];
Statement* S;
for (S = bb->getFirstStmt(rit, sit); S; S = bb->getNextStmt(rit, sit)) {
// if S is not a phi function (per Appel)
/* if (!S->isPhi()) */ {
// For each use of some variable x in S (not just assignments)
LocationSet locs;
if (S->isPhi()) {
PhiAssign* pa = (PhiAssign*)S;
Exp* phiLeft = pa->getLeft();
if (phiLeft->isMemOf() || phiLeft->isRegOf())
phiLeft->getSubExp1()->addUsedLocs(locs);
// A phi statement may use a location defined in a childless call, in which case its use collector
// needs updating
PhiAssign::iterator pp;
for (pp = pa->begin(); pp != pa->end(); ++pp) {
Statement* def = pp->def;
if (def && def->isCall())
((CallStatement*)def)->useBeforeDefine(phiLeft->clone());
}
}
else { // Not a phi assignment
S->addUsedLocs(locs);
}
LocationSet::iterator xx;
for (xx = locs.begin(); xx != locs.end(); xx++) {
Exp* x = *xx;
// Don't rename memOfs that are not renamable according to the current policy
if (!canRename(x, proc)) continue;
Statement* def = NULL;
if (x->isSubscript()) { // Already subscripted?
// No renaming required, but redo the usage analysis, in case this is a new return, and also because
// we may have just removed all call livenesses
// Update use information in calls, and in the proc (for parameters)
Exp* base = ((RefExp*)x)->getSubExp1();
def = ((RefExp*)x)->getDef();
if (def && def->isCall()) {
// Calls have UseCollectors for locations that are used before definition at the call
((CallStatement*)def)->useBeforeDefine(base->clone());
continue;
}
// Update use collector in the proc (for parameters)
if (def == NULL)
proc->useBeforeDefine(base->clone());
continue; // Don't re-rename the renamed variable
}
// Else x is not subscripted yet
if (STACKS_EMPTY(x)) {
if (!Stacks[defineAll].empty())
def = Stacks[defineAll].top();
else {
// If the both stacks are empty, use a NULL definition. This will be changed into a pointer
// to an implicit definition at the start of type analysis, but not until all the m[...]
// have stopped changing their expressions (complicates implicit assignments considerably).
def = NULL;
// Update the collector at the start of the UserProc
proc->useBeforeDefine(x->clone());
}
}
else
def = Stacks[x].top();
if (def && def->isCall())
// Calls have UseCollectors for locations that are used before definition at the call
((CallStatement*)def)->useBeforeDefine(x->clone());
// Replace the use of x with x{def} in S
changed = true;
if (S->isPhi()) {
Exp* phiLeft = ((PhiAssign*)S)->getLeft();
phiLeft->setSubExp1(phiLeft->getSubExp1()->expSubscriptVar(x, def /*, this*/));
} else {
S->subscriptVar(x, def /*, this */);
}
}
}
// MVE: Check for Call and Return Statements; these have DefCollector objects that need to be updated
// Do before the below, so CallStatements have not yet processed their defines
if (S->isCall() || S->isReturn()) {
DefCollector* col;
if (S->isCall())
col = ((CallStatement*)S)->getDefCollector();
else
col = ((ReturnStatement*)S)->getCollector();
col->updateDefs(Stacks, proc);
}
// For each definition of some variable a in S
//.........这里部分代码省略.........