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C++ DoublyLinkedList::clear方法代码示例

本文整理汇总了C++中DoublyLinkedList::clear方法的典型用法代码示例。如果您正苦于以下问题:C++ DoublyLinkedList::clear方法的具体用法?C++ DoublyLinkedList::clear怎么用?C++ DoublyLinkedList::clear使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在DoublyLinkedList的用法示例。


在下文中一共展示了DoublyLinkedList::clear方法的3个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。

示例1: main

int main()
{
	if(runTests())
	{
		DoublyLinkedList<int> list;
		unsigned int numberOfPeople;
		unsigned int currentIndex;

		list.clear();
		for (unsigned int count = 0; count < numberOfPeople; ++count)
		{
			list.pushBack(count + 1);
		}

		while(numberOfPeople > 1)
		{
			for (unsigned int skip = 0; skip < 33; ++skip)
			{
				currentIndex++;
				if( currentIndex > list.size() )
					currentIndex = 1;
			}
				list.removeAt(currentIndex-1);
				numberOfPeople--;
		}

		cout << "Person number: " << list.popBack() << "is left" << endl;
	}
	return 0;
}
开发者ID:Pufferfiz,项目名称:Portfolio,代码行数:30,代码来源:Driver.cpp

示例2: main

int main(int argc, char *argv[])
{
	cout << "[+] doubly linked list test program" << endl;
	DoublyLinkedList<int> dlist;
	test<bool>(dlist.empty(), true, "empty test1");
	dlist.addFront(1);
	dlist.addFront(2);
	dlist.addBack(3);
	test<bool>(dlist.empty(), false, "empty test2");
	test<int>(dlist.front(), 2, "front test");
	test<int>(dlist.back(), 3, "back test");
	dlist.removeBack();
	test<int>(dlist.back(), 1, "remove test1");
	dlist.removeFront();
	test<int>(dlist.front(), 1, "remove test2");
	dlist.clear();
	test<bool>(dlist.empty(), true, "clear test");

	return EXIT_SUCCESS;
}
开发者ID:pyowonil,项目名称:tools,代码行数:20,代码来源:test_doubly_linked_list.cpp

示例3: main

int main()
{
	DoublyLinkedList *ls = new DoublyLinkedList();
	ls->push_back(*(new ListNode("100")));
	ListNode *n1 = new ListNode("5");
	ls->push_front(*n1);
	ls->push_front(*(new ListNode("1")));
	ls->push_front(*(new ListNode("3")));
	ls->push_front(*(new ListNode("4")));
	ls->push_front(*(new ListNode("0")));
	ls->push_back(*(new ListNode("1sdsd")));
	ls->print();
	cout << "\n";
	ls->print_bkw();
	cout << "\nLink list size is equal to " << ls->size() << endl;
	cout << "\n";
	cout << "Lets delete first and last nodes from list\n";
	ls->pop_back();
	ls->pop_front();
	ls->print();
	cout << "\nNow lets erase 4, 1 and 100: \n";
	ls->erase("4");
	ls->erase("1");
	ls->erase("100");
	ls->print();
	cout << "\nLets insert '6' after '3' and '7' after '5': \n";
	ls->insert_after("3", *(new ListNode("6")));
	ls->insert_after("5", *(new ListNode("7")));
	ls->print();
	cout << "\nLets clear linked list (check this with 'isEmpty' method): \n";
	ls->clear();
	if (ls->isEmpty())
		cout << "Our list is empty! \n";
	cout << "\nLets get new list: \n";
	ls->push_front(*(new ListNode("6")));
	ls->push_front(*(new ListNode("31")));
	ls->push_front(*(new ListNode("55")));
	ls->push_front(*(new ListNode("4")));
	ls->push_front(*(new ListNode("1")));
	ls->push_front(*(new ListNode("3")));
	ls->push_front(*(new ListNode("4")));
	ls->push_front(*(new ListNode("8"))); 
	ls->push_front(*(new ListNode("5")));
	ls->push_front(*(new ListNode("0")));
	ls->print();
	cout << "\nOur new sorted list: \n";
	ls->sort();
	ls->print();
	cout << "\nLets delete unique elements: \n";
	ls->unique();
	ls->print();
	cout << "\nLets insert '0', '2', '7' and '9' preserving list ordering: \n";
	ls->insert_ord(*(new ListNode("0")));
	ls->insert_ord(*(new ListNode("2")));
	ls->insert_ord(*(new ListNode("7")));
	ls->insert_ord(*(new ListNode("9")));
	ls->print();

	cout << "\nLets get new list 'temp_ls': \n";
	DoublyLinkedList *temp_ls = new DoublyLinkedList();
	temp_ls->push_front(*(new ListNode("b")));
	temp_ls->push_front(*(new ListNode("v")));
	temp_ls->push_front(*(new ListNode("a")));
	temp_ls->push_front(*(new ListNode("d")));
	temp_ls->print();
	cout << "\nLets 'merge' our lists (temp_ls in ls): \n";
	ls->merge(*temp_ls);
	ls->print();
	if (temp_ls->isEmpty())
		cout << "Our 'temp_ls' list is empty! \n";
	cout << "\nLets get new lists: \n";
	ls->clear();
	ls->push_front(*(new ListNode("6")));
	ls->push_front(*(new ListNode("3")));
	ls->push_front(*(new ListNode("5")));
	ls->push_front(*(new ListNode("4")));
	ls->push_front(*(new ListNode("1")));
	cout << "New 'ls': ";
	ls->print();
	temp_ls->push_front(*(new ListNode("b")));
	temp_ls->push_front(*(new ListNode("v")));
	temp_ls->push_front(*(new ListNode("a")));
	temp_ls->push_front(*(new ListNode("d")));
	cout << "New 'temp_ls': ";
	temp_ls->print();
	cout << "\nLets assign 'ls' to 'temp_ls' from 1 to 3: \n";
	ls->assign(*temp_ls, 1, 3);
	cout << "New 'ls': ";
	ls->print();
	cout << "New 'temp_ls': ";
	temp_ls->print();
	cout << "\nLets splice 'temp_ls' in 'ls' from index 3 with all list:\n ";
	ls->splice(3, *temp_ls);
	ls->print();
	ls->clear();
	temp_ls->clear();
	ls->push_front(*(new ListNode("6")));
	ls->push_front(*(new ListNode("3")));
	ls->push_front(*(new ListNode("5")));
	ls->push_front(*(new ListNode("4")));
//.........这里部分代码省略.........
开发者ID:Caparow,项目名称:CPP-tasks,代码行数:101,代码来源:TestAndDemonstration.cpp


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