本文整理汇总了C++中Dog::getfeed方法的典型用法代码示例。如果您正苦于以下问题：C++ Dog::getfeed方法的具体用法？C++ Dog::getfeed怎么用？C++ Dog::getfeed使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Dog的用法示例。
在下文中一共展示了Dog::getfeed方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: main
void main() {
int count = 0;
bool flag = true;
cout << "How many Pets do you want to buy" << endl;
int nmbr;
cin >> nmbr;
Pet **pt = new Pet*[nmbr];
while (flag == true && count < nmbr) {
cout << "\t\t\tWelcome to Pet Shop system" << endl;
cout << "\tPlease select the pet" << endl;
cout << "1-Dog" << endl;
cout << "2-Cat" << endl;
cout << "3-Lion" << endl;
cout << "4-GoldFish" << endl;
cout << "5-Parrot" << endl;
cout << "6-Horse" << endl;
cout << "0-Exit" << endl;
int choice;
cin >> choice;
cout << endl << endl;
if (choice == 0) {
flag = false;
}
if (choice == 1)
{
Dog *a = new Dog;
cout << "I " << a->getsound() << endl;
cout << "I eat " << a->getfeed() << endl;
cout << "Will you like to buy me?(Y/N)" << endl;
char ch;
cin >> ch;
if (ch == 'y' || ch == 'Y')
{
if (count == 0) {
cout << "Pet Added" << endl;
count++;
pt = new Pet*[1];
pt[0] = a;
}
else {
bool flag = true;
for (int i = 0; i < count; i++) {
if (pt[i]->getname() == "Cat" || pt[i]->getname() == "GoldFish" || pt[i]->getname() == "Lion") {
flag = false;
}
i++;
}
if (flag == false) {
try
{
throw PetNotCompatibleException();
}
catch (PetNotCompatibleException& e)
{
cout << e.what() << endl;
}
char choice;
cin >> choice;
if (choice == 'y' || choice == 'Y') {
cout << "Pet Added" << endl;
pt[count] = a;
count++;
}
}
else {
cout << "Pet Added" << endl;
pt[count] = a;
count++;
}
}
}
else if (ch == 'N' || ch == 'n')