本文整理汇总了C++中CAEChannelInfo::AddMissingChannels方法的典型用法代码示例。如果您正苦于以下问题：C++ CAEChannelInfo::AddMissingChannels方法的具体用法？C++ CAEChannelInfo::AddMissingChannels怎么用？C++ CAEChannelInfo::AddMissingChannels使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类CAEChannelInfo的用法示例。
在下文中一共展示了CAEChannelInfo::AddMissingChannels方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: BestMatch
int CAEChannelInfo::BestMatch(const std::vector<CAEChannelInfo>& dsts, int* score) const
{
CAEChannelInfo availableDstChannels;
for (unsigned int i = 0; i < dsts.size(); i++)
availableDstChannels.AddMissingChannels(dsts[i]);
/* if we have channels not existing in any destination layout but that
* are remappable (e.g. RC => RL+RR), do those remaps */
CAEChannelInfo src(*this);
src.ResolveChannels(availableDstChannels);
bool remapped = (src != *this);
/* good enough approximation (does not account for added channels) */
int dropped = std::max((int)src.Count() - (int)Count(), 0);
int bestScore = std::numeric_limits<int>::min();
int bestMatch = -1;
for (unsigned int i = 0; i < dsts.size(); i++)
{
const CAEChannelInfo& dst = dsts[i];
int okChannels = 0;
for (unsigned int j = 0; j < src.Count(); j++)
okChannels += dst.HasChannel(src[j]);
int missingChannels = src.Count() - okChannels;
int extraChannels = dst.Count() - okChannels;
int curScore = 0 - (missingChannels + dropped) * 1000 - extraChannels * 10 - (remapped ? 1 : 0);
if (curScore > bestScore)
{
bestScore = curScore;
bestMatch = i;
if (curScore == 0)
break;
}
}
if (score)
*score = bestScore;
return bestMatch;
}