本文整理汇总了C++中BIT::init方法的典型用法代码示例。如果您正苦于以下问题：C++ BIT::init方法的具体用法？C++ BIT::init怎么用？C++ BIT::init使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类BIT的用法示例。
在下文中一共展示了BIT::init方法的10个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: main
int main() {
ios_base::sync_with_stdio(false);
int n, m, k;
int x, y;
cin >> n >> m >> k;
op.init(m+10);
a.init(n+10);
for (int i=1; i<=n; ++i) {
cin >> x;
a.add_interval(i, i, x);
}
for (int i=1; i<=m; ++i) cin >> l[i] >> r[i] >> d[i];
for (int i=0; i<k; ++i) {
cin >> x >> y;
op.add_interval(x, y, 1);
}
for (int i=1; i<=m; ++i) a.add_interval(l[i], r[i], op.sum(i)*d[i]);
for (int i=1; i<=n; ++i) cout << a.sum(i) << (i < n ? " " : "\n");
return 0;
}示例2: init
void init(Graph *g)
{
G=g;
bit.init(G->ndn);
dfst=0; dept[1] = 0; fath[1] = 0;
CLR(dfsn); CLR(bson); CLR(ntop);
dfs1(1);
dfs2(1,1);
}示例3: main
int main() {
while (~sf("%d", &n)) {
REP(i, n) {
sf("%s", op[i]);
if (op[0] == 'D' || op[0] == 'Q') {
sf("%d%d", &seg[i][0], &seg[i][1]);
b.pb(seg[i][0]);
b.pb(seg[i][1]);
}
else {
sf("%d", &seg[i][0]);
b.pb(seg[i][0]);
}
}
sort(all(b));
b.resize(unique(all(b))-b.begin());
le.init(b.size());
ri.init(b.size());
}示例4: main
int main()
{
#ifdef LOCAL
freopen("in.txt", "r", stdin);
// freopen("out.txt", "w", stdout);
#endif
int T;
scanf("%d", &T);
for(int ck=1; ck<=T; ck++)
{
scanf("%d", &Q);
D.siz=0;
CLR(ans);
int scnt=0;
for(int i=1; i<=Q; i++)
{
int opt,l,r;
scanf("%d%d", &opt, &l);
arry[i].t=i;
if(!opt)
{
scanf("%d", &r);
scnt++;
inpt[scnt][0] = l;
inpt[scnt][1] = r;
inpt[scnt][2] = i;
arry[i].l = l;
arry[i].r = r;
arry[i].v = 1;
D.add(l); D.add(r);
}
else
{
arry[i].l = inpt[l][0];
arry[i].r = inpt[l][1];
arry[i].v = -1;
}
}
D.init();
bit.init(D.siz);
for(int i=1; i<=Q; i++)
{
arry[i].l = D.id(arry[i].l);
arry[i].r = D.id(arry[i].r);
}
CDQ(1,Q);
for(int i=1; i<=scnt; i++) printf("%d\n", ans[ inpt[i][2] ]);
}
return 0;
}示例5: getMinimumInversions
int getMinimumInversions(vector <int> A, vector <int> B, vector <int> V, int K) {
n = (int)A.size();
edge = IVV(n);
vertex = V;
for (int i = 0; i < n; ++i) {
edge[A[i]].push_back(B[i]);
edge[B[i]].push_back(A[i]);
}
int ans = 1e6;
for (int i = 0; i < n; ++i) {
memset(visited, 0, sizeof(visited));
bit.init(1001);
ans = min(ans, dfs(i, K));
}
return (ans < 1e6) ? ans : -1;
}示例6: main
int main() {
int C = 0, T, q, x, y;
scanf("%d", &T);
while (++C <= T) {
bit.init();
scanf("%d", &n);
for (int i = 1; i <= n; i++) {
scanf("%d", &x);
bit.modify(i, x);
}
scanf("%d", &q);
while (q--) {
scanf("%d %d", &x, &y);
printf("%d\n", bit.query(x, y));
}
}
}示例7: calc
int calc(int p) {
printf("calc(%d)\n", p);
int cnt[20];
memset(cnt, 0, sizeof cnt);
int max_power = 0;
memset(power, 0, sizeof power);
for(int i = 0; i < n; i++) {
int num = v[i];
while(num % p == 0) {
power[i]++;
num /= p;
}
cnt[power[i]]++;
max_power = max(max_power, power[i]);
}
printf("max_power=%d ", max_power);
bit.init();
for(int i = 1; i <= max_power; i++) {
bit.add(i, cnt[i]);
}
int ans = 0;
int cur = p;
int base[20];
for(int i = 1; cur <= maxa; i++) {
base[i] = cur;
cur = (cur * 1LL * p) % mod;
}
for(int i = 0; i < n; i++) {
if(power[i] == 0)
continue;
printf("total(%d - %d)=%d ", bit.sum(max_power), bit.sum(power[i] - 1), total(bit.sum(max_power) - bit.sum(power[i] - 1)));
ans = (ans + (base[power[i]] * 1LL * total(bit.sum(max_power) - bit.sum(power[i] - 1))) % mod) % mod;
printf("i=%d ans=%d ", i, ans);
for(int j = power[i] - 1; j >= 1; j--) {
ans = (ans + (base[j] * 1LL * total(cnt[j])) % mod) % mod;
printf("cnt[%d]=%d ans=%d ", j, cnt[j], ans);
}
printf("ans=%d\n", ans);
cnt[power[i]]--;
bit.add(power[i], -1);
}
return ans;
}示例8: main
int main() {
int x, r, h;
int a, b;
scanf("%d%d", &N, &Q);
bit.init(MAX_X + MAX_H);
for (int i = 0; i < N; i++) {
scanf("%d%d%d", &x, &r, &h);
for (int j = 0; j < h; j++) {
bit.add(x + j + 1, (double)r * r * M_PI * h * 1.0/3.0 * (pow(h - j, 3) - pow(h - j - 1, 3)) / pow(h, 3));
}
}
for (int i = 0; i < Q; i++) {
scanf("%d%d", &a, &b);
ans = bit.sum(b) - bit.sum(a);
printf("%lf\n", ans);
}
return 0;
}示例9: init
void init() {
bit.init();
REP(i,MXN) col[i].clear();
}示例10: main
int main()
{
int T, ca=0, ti = 0, a, bb, sum, le, ri;
char op[10];
vi p1, p2;
scanf("%d", &T);
while (T--)
{
scanf("%d%d%d", &n, &Q, &t);
// n+=2;
ans.init();
seg.init();
point.clear();
ti=0;
printf("Case %d:\n", ++ca);
for (int i=0; i<Q; i++)
{
scanf("%s", op);
if (op[0]=='A')
{
ti++;
scanf("%d%d", &que[ti][0], &que[ti][1]);
que[ti][0] += 2; que[ti][1] += 2;
// cout <<ti << " "<<t<<endl;
if (ti-t>=1)
{
seg.insert_seg(que[ti-t][0], que[ti-t][1], -1);
point.erase(lower_bound(point.begin(), point.end(), que[ti-t][0]));
point.erase(lower_bound(point.begin(), point.end(), que[ti-t][1]));
}
if (point.size()>=2){
vi pp = point.end();
pp--;
le = max(*point.begin(), que[ti][0]);
ri = min(*pp, que[ti][1]);
if (le > ri)
{
le = que[ti][0];
ri = que[ti][1];
}
cout <<le-2 <<" "<<ri-2 <<"----"<<*point.begin() <<" "<<*pp <<endl;
ans.updata(ri-2, 1);
ans.updata(le-1-2, -1);
}
point.insert(que[ti][0]);
point.insert(que[ti][1]);
if (ti-t>=1)
{
le = max(que[ti-t][0], le);
ri = min(ri, que[ti-t][1]);
cout <<le-2 <<" "<<ri-2<<" recovery" <<endl;
ans.updata(ri-2, -1);
ans.updata(le-1-2, 1);
le = n+2; ri = 2;
if (ti-t-1>=1){
for (int j=ti-t-1; j+t>=ti-t && j+t<ti; j--)
{
// if (j < 1) break;
le = min(le, que[j][0]);
ri = max(ri, que[j][1]);
}
le = max(le, que[ti-t][0]);
ri = min(ri, que[ti-t][1]);
// cout <<le-2 <<" "<<ri-2<<" add" <<endl;
ans.updata(ri-2, 1);
ans.updata(le-1-2, -1);
}
}
}
else
{
scanf("%d", &bb);
printf("%d\n", ans.query(bb));
}
}
}
system("pause");
return 0;
}