本文整理汇总了C++中AuthorizationSession::isAuthenticatedAsUserWithRole方法的典型用法代码示例。如果您正苦于以下问题：C++ AuthorizationSession::isAuthenticatedAsUserWithRole方法的具体用法？C++ AuthorizationSession::isAuthenticatedAsUserWithRole怎么用？C++ AuthorizationSession::isAuthenticatedAsUserWithRole使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类AuthorizationSession的用法示例。
在下文中一共展示了AuthorizationSession::isAuthenticatedAsUserWithRole方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: checkAuthForRolesInfoCommand
Status checkAuthForRolesInfoCommand(ClientBasic* client,
const std::string& dbname,
const BSONObj& cmdObj) {
AuthorizationSession* authzSession = AuthorizationSession::get(client);
auth::RolesInfoArgs args;
Status status = auth::parseRolesInfoCommand(cmdObj, dbname, &args);
if (!status.isOK()) {
return status;
}
if (args.allForDB) {
if (!authzSession->isAuthorizedForActionsOnResource(
ResourcePattern::forDatabaseName(dbname), ActionType::viewRole)) {
return Status(ErrorCodes::Unauthorized,
str::stream() << "Not authorized to view roles from the " << dbname
<< " database");
}
} else {
for (size_t i = 0; i < args.roleNames.size(); ++i) {
if (authzSession->isAuthenticatedAsUserWithRole(args.roleNames[i])) {
continue; // Can always see roles that you are a member of
}
if (!authzSession->isAuthorizedForActionsOnResource(
ResourcePattern::forDatabaseName(args.roleNames[i].getDB()),
ActionType::viewRole)) {
return Status(ErrorCodes::Unauthorized,
str::stream() << "Not authorized to view roles from the "
<< args.roleNames[i].getDB() << " database");
}
}
}
return Status::OK();
}