本文整理汇总了C++中Argument::getLongArg方法的典型用法代码示例。如果您正苦于以下问题：C++ Argument::getLongArg方法的具体用法？C++ Argument::getLongArg怎么用？C++ Argument::getLongArg使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Argument的用法示例。
在下文中一共展示了Argument::getLongArg方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: addArgument
void ArgumentParser::addArgument(const Argument& arg) {
vargs.push_back(arg);
if (arg.getShortArg().size() > 0) {
args.insert(pair<string, Argument>(arg.getShortArg(), arg));
}
if (arg.getLongArg().size() > 0) {
args.insert(pair<string, Argument>(arg.getLongArg(), arg));
}
}示例2: parse
ParsedArgument ArgumentParser::parse(int argc, char** argv) {
// put all the arguments into vector for easy manipulation
vector<string> v;
for (int i = 1; i < argc; i++) {
v.push_back(string(argv[i]));
}
ParsedArgument pa;
// ignore the first argument since the first argument is a program name
for (size_t i = 0; i < v.size(); ++i) {
string s = v[i];
bool shortArg = cppargparser::isShortArg(s);
bool longArg = cppargparser::isLongArg(s);
if (!shortArg && !longArg) {
throw InvalidArgumentException(s + " is an invalid argument");
}
string arg = s;
if (longArg) {
// if the argument has =, e.g. ---ccc=123 split it by = and then
// modify the vector by modifying --ccc=123 with --ccc and adding
// a new element 123
size_t index = arg.find("=");
if (index != string::npos) {
string key = arg.substr(0, index);
string value = arg.substr(index+1);
arg = key;
v[i] = key;
v.insert(v.begin()+i+1, value);
}
}
map<string, Argument>::iterator it = args.find(arg);
if (it == args.end()) {
throw InvalidArgumentException(arg + " is an invalid argument");
}
Argument argument = it->second;
if (argument.getNumArgs() == Argument::INFINITY) {
string value = "";
do {
value = v[++i];
if (!cppargparser::isShortArg(value)) {
pa.putArgument(argument.getShortArg(), value);
}
if (!cppargparser::isLongArg(value)) {
pa.putArgument(argument.getLongArg(), value);
}
} while (!isShortArg(value) && !isLongArg(value));
} else {
i = i + 1;
size_t n = i + argument.getNumArgs();
// this condition means there's the argument doesn't need any value,
// i.e. the numArgs is 0, thus there's no need to iterate each
// argument value
if (i == n) {
pa.putArgument(argument.getShortArg(), "");
pa.putArgument(argument.getLongArg(), "");
}
else {
for (; i < n; ++i) {
if (i >= v.size()) {
throw InvalidArgumentException(
argument.getArg() + " requires " +
cppargparser::toString(argument.getNumArgs()) +
" argument(s)");
}
string value = v[i];
pa.putArgument(argument.getShortArg(), value);
pa.putArgument(argument.getLongArg(), value);
}
}
}
Validator* validator = argument.getValidator();
if (validator != NULL) {
if (argument.isShortArg()) {
vector<string> values = pa.getValues(argument.getShortArg());
if (!validator->validate(values)) {
throw InvalidArgumentException(cppargparser::toString(values) +
" is an invalid argument value");
}
} else {
vector<string> values = pa.getValues(argument.getLongArg());
if (!validator->validate(values)) {
throw InvalidArgumentException(cppargparser::toString(values) +
" is an invalid argument value");
}
}
}
args.erase(argument.getShortArg());
args.erase(argument.getLongArg());
// need to decrement i here because both inner and outer loops
// increment i by 1
--i;
}
// check if the there are still mandatory arguments in the args map
// if there are, throw an InvalidArgumentException
for (map<string, Argument>::const_iterator i = args.begin(); i != args.end(); ++i) {
if (i->second.isMandatory()) {
throw InvalidArgumentException(i->second.getArg() +
" is a mandatory argument");
}
}
//.........这里部分代码省略.........