本文整理汇总了C++中ACE_SOCK_Dgram::recv方法的典型用法代码示例。如果您正苦于以下问题：C++ ACE_SOCK_Dgram::recv方法的具体用法？C++ ACE_SOCK_Dgram::recv怎么用？C++ ACE_SOCK_Dgram::recv使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类ACE_SOCK_Dgram的用法示例。
在下文中一共展示了ACE_SOCK_Dgram::recv方法的4个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: run_receiver
/*\brief Receive single datagram
\note The function employes dgram_port and dgram_recv_timeout variables
\retval -1 if not received,
\retval 0 received a datagrams
*/
int run_receiver ()
{
ACE_DEBUG
((LM_INFO,
ACE_TEXT ("Receiving datagrams from port %d with timeout %d ms\n"),
dgram_port, dgram_recv_timeout.msec ()));
ACE_SOCK_Dgram socket;
ACE_INET_Addr remote ;
static char dgram_buffer[BUFSIZ];
if (socket.open (ACE_INET_Addr (dgram_port)) != -1)
if (socket.recv (dgram_buffer, sizeof (dgram_buffer),
remote, 0, &dgram_recv_timeout) > 0)
{
ACE_DEBUG ((LM_INFO, ACE_TEXT ("%C received\n"), dgram_buffer));
return 0;
}
else
{
ACE_ERROR_RETURN ((LM_ERROR, ACE_TEXT ("%p\n"),
ACE_TEXT ("Cannot receive datagrams")), -1);
}
else
{
ACE_ERROR_RETURN ((LM_ERROR,
ACE_TEXT ("%p: %d\n"),
ACE_TEXT ("Cannot open broadcast socket on port"), dgram_port), -1);
}
}示例2: echo_dgram
// Listing 2 code/ch09
void echo_dgram (void)
{
ACE_INET_Addr my_addr (ACE_static_cast (u_short, 10102));
ACE_INET_Addr your_addr;
ACE_SOCK_Dgram udp (my_addr);
char buff[BUFSIZ];
size_t buflen = sizeof (buff);
ssize_t recv_cnt = udp.recv (buff, buflen, your_addr);
if (recv_cnt > 0)
udp.send (buff, ACE_static_cast (size_t, buflen), your_addr);
udp.close ();
return;
}示例3: handle_input
int DgramHandler::handle_input (ACE_HANDLE)
{
int recvBuffer;
ACE_INET_Addr peerAddress;
int result = peer_.recv (&recvBuffer, sizeof (recvBuffer) , peerAddress);
if (0 >= result)
ACE_ERROR_RETURN ((LM_ERROR,
ACE_TEXT (" (%P) %p\n"),
ACE_TEXT ("While reading datagram from socket"))
, -1);
else
++dgramsReceived_;
return 0;
}示例4: mypid
//.........这里部分代码省略.........
mutex_name.c_str ());
if (child->spawn (options) == -1)
{
ACE_ERROR_RETURN ((LM_ERROR,
ACE_TEXT ("spawn of child %d %p\n"),
i,
ACE_TEXT ("failed")),
-1);
}
else
{
ACE_DEBUG ((LM_DEBUG,
ACE_TEXT ("Child process %d has pid = %d.\n"),
i,
(int)(child->getpid ())));
}
}
// Keep reading time ranges reported from the children until all the
// children have exited. Alternate between checking for a range and
// checking for exits.
int processes = Nr_Processes;
Child *children[Nr_Processes];
for (i = 0; i < Nr_Processes; i++)
children[i] = (i == 0 ? &writer : &readers[i-1]);
Range_Report report;
ACE_Time_Value poll (0);
ACE_INET_Addr from;
ssize_t bytes;
while (processes > 0)
{
ACE_Time_Value limit (10);
bytes = sock.recv (&report, sizeof (report), from, 0, &limit);
if (bytes > 0)
{
ACE_DEBUG ((LM_DEBUG,
ACE_TEXT ("Report from child %d; %b bytes\n"),
report.child_, bytes));
if (report.child_ == 0)
writer.add_range (report.range_);
else
{
if (report.child_ >= 1 && report.child_ < Nr_Processes)
readers[report.child_ - 1].add_range (report.range_);
else
ACE_ERROR ((LM_ERROR,
ACE_TEXT ("Report from out-of-range child #%d\n"),
report.child_));
}
}
else
{
if (errno == ETIME)
ACE_DEBUG ((LM_DEBUG,
ACE_TEXT ("UDP time out; check child exits\n")));
else
ACE_ERROR ((LM_ERROR, ACE_TEXT ("%p\n"), ACE_TEXT ("UDP recv")));
}
for (i = 0; i < Nr_Processes; i++)
{
if (children[i] == 0)
continue;
ACE_exitcode child_status;
// See if the child has exited.