如果此掃描器的輸入中還有另一行,則java.util.Scanner類的hasNextLine()方法將返回true。等待輸入時,此方法可能會阻塞。掃描儀不會越過任何輸入。
用法:
public boolean hasNextLine()
參數:該函數不接受任何參數。
返回值:當且僅當此掃描儀具有另一行輸入時,此函數才返回true
異常注意:如果關閉此掃描器,則此函數將引發IllegalStateException。
以下示例程序旨在說明上述函數:
示例1:
// Java program to illustrate the
// hasNextLine() method of Scanner class in Java
// without parameter
import java.util.*;
public class GFG1 {
public static void main(String[] argv)
throws Exception
{
String s = "gfg 2 geeks!";
// new scanner with the
// specified String Object
Scanner scanner = new Scanner(s);
// use US locale to interpret Lines in a string
scanner.useLocale(Locale.US);
// iterate till end
while (scanner.hasNextLine()) {
// print what is scanned
System.out.println(scanner.nextLine());
}
// close the scanner
scanner.close();
}
}
輸出:
gfg 2 geeks!
示例2:演示異常的程序
// Java program to illustrate the
// hasNextLine() method of Scanner class in Java
// without parameter
import java.util.*;
public class GFG1 {
public static void main(String[] argv)
throws Exception
{
try {
String s = "gfg 2 geeks!";
// new scanner with the
// specified String Object
Scanner scanner = new Scanner(s);
// use US locale to interpret Lines in a string
scanner.useLocale(Locale.US);
scanner.close();
// iterate till end
while (scanner.hasNextLine()) {
// print what is scanned
System.out.println(scanner.nextLine());
}
// close the scanner
scanner.close();
}
catch (IllegalStateException e) {
System.out.println("Exception is: " + e);
}
}
}
輸出:
Exception is: java.lang.IllegalStateException: Scanner closed
參考: https://docs.oracle.com/javase/7/docs/api/java/util/Scanner.html#hasNextLine()
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