numpy.round_(arr, decimals = 0, out = None)：此數學函數將數組四舍五入為給定的小數位數。
參數：
-
array : [數組]輸入數組。
decimal : [int，可選]我們要舍入的小數位。 - out : [可選的]輸出結果數組
默認值=0。如果是-ve十進製，則指定n0。小數點左邊的位置。
返回：
An array with all array elements being rounded off, having same type as input.
代碼1：工作
# Python program explaining
# round_() function
import numpy as np
in_array = [.5, 1.5, 2.5, 3.5, 4.5, 10.1]
print ("Input array : \n", in_array)
round_off_values = np.round_(in_array)
print ("\nRounded values : \n", round_off_values)
in_array = [.53, 1.54, .71]
print ("\nInput array : \n", in_array)
round_off_values = np.round_(in_array)
print ("\nRounded values : \n", round_off_values)
in_array = [.5538, 1.33354, .71445]
print ("\nInput array : \n", in_array)
round_off_values = np.round_(in_array, decimals = 3)
print ("\nRounded values : \n", round_off_values)輸出：
Input array : [0.5, 1.5, 2.5, 3.5, 4.5, 10.1] Rounded values : [ 0. 2. 2. 4. 4. 10.] Input array : [0.53, 1.54, 0.71] Rounded values : [ 1. 2. 1.] Input array : [0.5538, 1.33354, 0.71445] Rounded values : [ 0.554 1.334 0.714]
代碼2：工作
# Python program explaining
# round_() function
import numpy as np
in_array = [1, 4, 7, 9, 12]
print ("Input array : \n", in_array)
round_off_values = np.round_(in_array)
print ("\nRounded values : \n", round_off_values)
in_array = [133, 344, 437, 449, 12]
print ("\nInput array : \n", in_array)
round_off_values = np.round_(in_array, decimals = -2)
print ("\nRounded values upto 2: \n", round_off_values)
in_array = [133, 344, 437, 449, 12]
print ("\nInput array : \n", in_array)
round_off_values = np.round_(in_array, decimals = -3)
print ("\nRounded values upto 3: \n", round_off_values)輸出：
Input array : [1, 4, 7, 9, 12] Rounded values : [ 1 4 7 9 12] Input array : [133, 344, 437, 449, 12] Rounded values upto 2: [100 300 400 400 0] Input array : [133, 344, 437, 449, 12] Rounded values upto 3: [0 0 0 0 0]
參考文獻： https://docs.scipy.org/doc/numpy-dev/reference/generated/numpy.round_.html#numpy.round_
。
相關用法
注：本文由純淨天空篩選整理自Mohit Gupta_OMG 大神的英文原創作品 numpy.round_() in Python。非經特殊聲明，原始代碼版權歸原作者所有，本譯文未經允許或授權，請勿轉載或複製。