Guava IntMath類的floorPowerOfTwo()方法接受一個參數,並返回比該參數中傳遞的值小2的最大冪。這等效於:checkedPow(2,log2(x,FLOOR))。
用法:
public static int floorPowerOfTwo(int x)
參數:此方法接受單個參數x,它是整數值。
返回值:該方法返回小於或等於x的2的最大冪。
異常:如果x <= 0,則方法floorPowerOfTwo(int x)拋出IllegalArgumentException。
範例1:
// Java code to show implementation
// of floorPowerOfTwo(int x) method
// of Guava's IntMath class
import java.math.RoundingMode;
import com.google.common.math.IntMath;
class GFG {
// Driver code
public static void main(String args[])
{
int n1 = 10;
// Using floorPowerOfTwo(int x) method
// of Guava's IntMath class
int ans1 = IntMath.floorPowerOfTwo(n1);
System.out.println("Largest power of 2 less "
+ "than or equal to " + n1 + " is:" + ans1);
int n2 = 127;
// Using floorPowerOfTwo(int x) method
// of Guava's IntMath class
int ans2 = IntMath.floorPowerOfTwo(n2);
System.out.println("Largest power of 2 less "
+ "than or equal to " + n2 + " is:" + ans2);
}
}
輸出:
Largest power of 2 less than or equal to 10 is:8 Largest power of 2 less than or equal to 127 is:64
範例2:
// Java code to show implementation
// of floorPowerOfTwo(int x) method
// of Guava's IntMath class
import java.math.RoundingMode;
import com.google.common.math.IntMath;
class GFG {
static int findFloorPow(int x)
{
try {
// Using floorPowerOfTwo(int x)
// method of Guava's IntMath class
// This should raise "IllegalArgumentException"
// as x <= 0
int ans = IntMath.floorPowerOfTwo(x);
// Return the answer
return ans;
}
catch (Exception e) {
System.out.println(e);
return -1;
}
}
// Driver code
public static void main(String args[])
{
int x = -3;
try {
// Function calling
findFloorPow(x);
}
catch (Exception e) {
System.out.println(e);
}
}
}
輸出:
java.lang.IllegalArgumentException:x (-3) must be > 0
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