d3.js中的node.leaves()函數用於按遍曆順序返回給定層次數據的葉節點數組。
用法:
node.leaves();
參數:該函數不接受任何參數。
返回值:該函數返回一個數組。
注意:葉節點是沒有子節點的那些節點。
下麵給出的是上麵給出的函數的一些例子。
範例1:
HTML
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8" />
<meta name="viewport" path1tent=
"width=device-width, initial-scale = 1.0" />
<script src="https://d3js.org/d3.v4.min.js">
</script>
</head>
<body>
<script>
// Constructing a tree
var tree = {
name:"rootNode",
children:[
{
name:"child1_leaf1"
},
{
name:"child2",
children:[
{
name:"grandchild1",
children:[
{ name:"leaf2" }
]
},
]
},
{
name:"child3",
children:[
{ name:"leaf3" },
{ name:"leaf4" },
]
}
]
};
var obj = d3.hierarchy(tree);
// Leaf nodes of the above given tree
console.log("Leaf nodes are:");
console.log(obj.leaves());
</script>
</body>
</html>
輸出:
範例2:以下代碼演示了訪問葉節點的數據。
HTML
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8" />
<meta name="viewport" path1tent=
"width=device-width, initial-scale = 1.0"/>
<script src="https://d3js.org/d3.v4.min.js">
</script>
</head>
<body>
<script>
// Constructing a tree
var tree = {
name:"rootNode",
children:[
{
name:"child1_leaf1"
},
{
name:"child2",
children:[
{
name:"grandchild1",
children:[
{ name:"leaf2" }
]
},
]
},
{
name:"child3",
children:[
{ name:"leaf3" },
{ name:"leaf4" },
]
}
]
};
var obj = d3.hierarchy(tree);
// Leaf nodes of the above given tree are:
console.log(" Accessing Leaf nodes:");
let leafArr = obj.leaves();
leafArr.forEach((e) => {
console.log(e.data);
console.log("depth:", e.depth);
})
</script>
</body>
</html>
輸出:
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注:本文由純淨天空篩選整理自tarun007大神的英文原創作品 D3.js node.leaves() Function。非經特殊聲明,原始代碼版權歸原作者所有,本譯文未經允許或授權,請勿轉載或複製。