Java ConcurrentSkipListSet remove()用法及代碼示例

java.util.concurrent.ConcurrentSkipListSet.remove()方法是Java中的內置函數，用於刪除元素(如果此集合中存在)。

用法:

ConcurrentSkipListSet.remove(Object o)

參數：該函數接受單個參數，即要刪除的對象。

返回值：成功刪除對象後，該函數將返回true布爾值，否則返回false。

以下示例程序旨在說明ConcurrentSkipListSet.remove()方法：

示例1:集合中存在要刪除的元素。

// Java Program Demonstrate remove() 
// method of ConcurrentSkipListSet 
  
import java.util.concurrent.ConcurrentSkipListSet; 
  
class ConcurrentSkipListSetRemoveExample1 { 
    public static void main(String[] args) 
    { 
        // Initializing the set 
        ConcurrentSkipListSet<Integer> set =  
                         new ConcurrentSkipListSet<Integer>(); 
  
        // Adding elements to this set 
        for (int i = 1; i <= 5; i++) 
            set.add(i); 
  
        // Printing the elements of the set 
        System.out.println("The elements in the set are:"); 
        for (Integer i : set) 
            System.out.print(i + " "); 
  
        // remove() method will remove the specified 
        // element from the set 
        set.remove(1); 
        set.remove(5); 
  
        // Printing the elements of the set 
        System.out.println("\nRemaining elements in set : "); 
        for (Integer i : set) 
            System.out.print(i + " "); 
    } 
}

輸出：

The elements in the set are:
1 2 3 4 5 
Remaining elements in set : 
2 3 4

示例2:集合中不存在要刪除的元素。

// Java Program Demonstrate remove() 
// method of ConcurrentSkipListSet 
  
import java.util.concurrent.ConcurrentSkipListSet; 
  
class ConcurrentSkipListSetRemoveExample2 { 
    public static void main(String[] args) 
    { 
        // Initializing the set 
        ConcurrentSkipListSet<Integer> set = 
                       new ConcurrentSkipListSet<Integer>(); 
  
        // Adding elements to this set 
        for (int i = 10; i <= 15; i++) 
            set.add(i); 
  
        // Printing the elements of the set 
        System.out.println("The elements in the set are:"); 
        for (Integer i : set) 
            System.out.print(i + " "); 
  
        // remove() method will remove the specified 
        // element from the set 
        set.remove(1); 
        set.remove(5); 
  
        // Printing the elements of the set 
        System.out.println("\nRemaining elements in set : "); 
        for (Integer i : set) 
            System.out.print(i + " "); 
    } 
}

輸出：

The elements in the set are:
10 11 12 13 14 15 
Remaining elements in set : 
10 11 12 13 14 15

參考： https://docs.oracle.com/javase/8/docs/api/java/util/concurrent/ConcurrentSkipListSet.html#remove-java.lang.Object-

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注：本文由純淨天空篩選整理自rupesh_rao大神的英文原創作品 ConcurrentSkipListSet remove() method in Java。非經特殊聲明，原始代碼版權歸原作者所有，本譯文未經允許或授權，請勿轉載或複製。