Java ConcurrentSkipListSet contains()用法及代碼示例

java.util.concurrent.ConcurrentSkipListSet的contains()方法是Java中的內置函數，如果指定的元素存在於此集合中，則該函數返回true布爾值，否則返回false。

用法:

ConcurrentSkipListSet.contains(Object o)

參數：該函數接受單個參數o，即檢查該參數是否存在。

返回值：該函數返回一個布爾值。如果指定的元素存在於此集中，則返回True；否則返回False。

以下示例程序旨在說明ConcurrentSkipListSet.contains()方法：

示例1:

// Java Program Demonstrate contains() 
// method of ConcurrentSkipListSet 
  
import java.util.concurrent.*; 
  
class ConcurrentSkipListSetContainsExample1 { 
    public static void main(String[] args) 
    { 
  
        // Initializing the set 
        ConcurrentSkipListSet<Integer> 
            set = new ConcurrentSkipListSet<Integer>(); 
  
        // Adding elements to this set 
        for (int i = 10; i <= 15; i++) 
            set.add(i); 
  
        // Checks if 9 is present in the set 
        if (set.contains(9)) 
            System.out.println("9 is present in the set."); 
        else
            System.out.println("9 is not present in the set."); 
    } 
}

輸出：

9 is not present in the set.

示例2:

// Java Program Demonstrate contains() 
// method of ConcurrentSkipListSet */ 
  
import java.util.concurrent.*; 
  
class ConcurrentSkipListSetContainsExample2 { 
    public static void main(String[] args) 
    { 
  
        // Initializing the set 
        ConcurrentSkipListSet<String> 
            set = new ConcurrentSkipListSet<String>(); 
  
        // Adding elements to this set 
        set.add("Gfg"); 
        set.add("is"); 
        set.add("fun"); 
  
        // Checks if Gfg is present in the set 
        if (set.contains("Gfg")) 
            System.out.println("Gfg is present in the set."); 
        else
            System.out.println("Gfg is not present in the set."); 
    } 
}

輸出：

Gfg is present in the set.

參考： https://docs.oracle.com/javase/8/docs/api/java/util/concurrent/ConcurrentSkipListSet.html#contains-java.lang.Object-

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注：本文由純淨天空篩選整理自rupesh_rao大神的英文原創作品 ConcurrentSkipListSet contains() method in Java。非經特殊聲明，原始代碼版權歸原作者所有，本譯文未經允許或授權，請勿轉載或複製。