Java CompoundName equals()用法及代碼示例

javax.naming.CompoundName類的equals()方法用於比較此CompoundName與作為參數傳遞的指定對象，並檢查兩個對象是否相等。如果兩個對象相等，則equals()方法返回true，否則返回false。如果傳遞的obj為null或不是複合名稱，則該方法返回false。如果一個組件中的每個組件與另一個組件中的相應組件相等，則兩個複合對象相等。

用法:

public boolean equals(Object obj)

參數：此方法接受obj，它是要與之比較的非null對象。

返回值：如果obj等於此複合名稱，則此方法返回true，否則返回false。

以下示例程序旨在說明CompoundName.equals()方法：
程序1:

// Java program to demonstrate 
// CompoundName.equals() 
  
import java.util.Properties; 
import javax.naming.CompoundName; 
import javax.naming.InvalidNameException; 
  
public class GFG { 
    public static void main(String[] args) 
        throws InvalidNameException 
    { 
  
        // need properties for CompoundName 
        Properties props = new Properties(); 
        props.put("jndi.syntax.separator", ":"); 
        props.put("jndi.syntax.direction", 
                  "left_to_right"); 
  
        // create compound name object 
        CompoundName CompoundName1 
            = new CompoundName( 
                "x:y:z", props); 
        CompoundName CompoundName2 
            = new CompoundName( 
                "x:y:m", props); 
  
        // apply equals() 
        boolean flag 
            = CompoundName1 
                  .equals(CompoundName2); 
  
        // print value 
        if (flag) 
            System.out.println( 
                "CompoundName1 is "
                + "equal to CompoundName2"); 
        else
            System.out.println( 
                "CompoundName1 is "
                + "not equal to CompoundName2"); 
    } 
}

輸出：

CompoundName1 is not equal to CompoundName2

程序2:

// Java program to demonstrate 
// CompoundName.equals() method 
  
import java.util.Properties; 
import javax.naming.CompoundName; 
import javax.naming.InvalidNameException; 
  
public class GFG { 
    public static void main(String[] args) 
        throws InvalidNameException 
    { 
  
        // need properties for CompoundName 
        Properties props = new Properties(); 
        props.put("jndi.syntax.separator", "@"); 
        props.put("jndi.syntax.direction", 
                  "left_to_right"); 
  
        // create compound name object 
        CompoundName CompoundName1 
            = new CompoundName( 
                "x@y@z@M@n", props); 
        CompoundName CompoundName2 
            = new CompoundName( 
                "x@y@z@M@n", props); 
  
        // apply equals() 
        boolean flag 
            = CompoundName1.equals(CompoundName2); 
  
        // print value 
        if (flag) 
            System.out.println( 
                "CompoundName1 is "
                + "equal to CompoundName2"); 
        else
            System.out.println( 
                "CompoundName1 is "
                + "not equal to CompoundName2"); 
    } 
}

輸出：

CompoundName1 is equal to CompoundName2

參考文獻：https://docs.oracle.com/javase/10/docs/api/javax/naming/CompoundName.html#equals(java.lang.Object)

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注：本文由純淨天空篩選整理自AmanSingh2210大神的英文原創作品 CompoundName equals() method in Java with Examples。非經特殊聲明，原始代碼版權歸原作者所有，本譯文未經允許或授權，請勿轉載或複製。