Java CompoundName compareTo()用法及代碼示例

javax.naming.CompoundName類的compareTo()方法用於比較此CompoundName與作為參數傳遞的指定對象。當此CompoundName對象小於，等於或大於給定Object作為參數時，它將返回負整數，零或正整數。如果傳遞的對象為null或不是CompoundName的實例，則此方法將引發ClassCastException。

用法:

public int compareTo(Object obj)

參數：此方法接受obj，它是要與之比較的非null對象。

返回值：此方法返回負整數，零或正整數，因為此Name小於，等於或大於給定的Object。

異常：如果傳遞的obj不是CompoundName對象，則此方法將引發ClassCastException。

以下示例程序旨在說明CompoundName.compareTo()方法：
程序1:

// Java program to demonstrate 
// CompoundName.compareTo() 
  
import java.util.Properties; 
import javax.naming.CompoundName; 
import javax.naming.InvalidNameException; 
  
public class GFG { 
    public static void main(String[] args) 
        throws InvalidNameException 
    { 
  
        // need properties for CompoundName 
        Properties props = new Properties(); 
        props.put("jndi.syntax.separator", ":"); 
        props.put("jndi.syntax.direction", 
                  "left_to_right"); 
  
        // create compound name object 
        CompoundName CompoundName1 
            = new CompoundName("x:y:z", 
                               props); 
        CompoundName CompoundName2 
            = new CompoundName("x:y:m", 
                               props); 
  
        // apply compareTo() 
        int value 
            = CompoundName1 
                  .compareTo(CompoundName2); 
  
        // print value 
        if (value > 0) 
            System.out.println( 
                "CompoundName1 is "
                + "greater than CompoundName2"); 
        else if (value < 0) 
            System.out.println( 
                "CompoundName1 is "
                + "smaller than CompoundName2"); 
        else
            System.out.println( 
                "CompoundName1 is "
                + "equal to CompoundName2"); 
    } 
}

輸出：

CompoundName1 is greater than CompoundName2

程序2:

// Java program to demonstrate 
// CompoundName.compareTo() method 
  
import java.util.Properties; 
import javax.naming.CompoundName; 
import javax.naming.InvalidNameException; 
  
public class GFG { 
    public static void main(String[] args) 
        throws InvalidNameException 
    { 
  
        // need properties for CompoundName 
        Properties props = new Properties(); 
        props.put("jndi.syntax.separator", "@"); 
        props.put("jndi.syntax.direction", 
                  "left_to_right"); 
  
        // create compound name object 
        CompoundName CompoundName1 
            = new CompoundName( 
                "x@y@z@M@n", 
                props); 
        CompoundName CompoundName2 
            = new CompoundName( 
                "x@y@z@M@n", 
                props); 
  
        // apply compareTo() 
        int value 
            = CompoundName1 
                  .compareTo(CompoundName2); 
  
        // print value 
        if (value > 0) 
            System.out.println( 
                "CompoundName1 is "
                + "greater than CompoundName2"); 
        else if (value < 0) 
            System.out.println( 
                "CompoundName1 is "
                + "smaller than CompoundName2"); 
        else
            System.out.println( 
                "CompoundName1 is "
                + "equal to CompoundName2"); 
    } 
}

輸出：

CompoundName1 is equal to CompoundName2

參考文獻：https://docs.oracle.com/javase/10/docs/api/javax/naming/CompoundName.html#compareTo(java.lang.Object)

相關用法

注：本文由純淨天空篩選整理自AmanSingh2210大神的英文原創作品 CompoundName compareTo() method in Java with Examples。非經特殊聲明，原始代碼版權歸原作者所有，本譯文未經允許或授權，請勿轉載或複製。